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5 (1)
5.1Design a resistive-load inverter with R = 2 kΩ, such that VOL = 0.05 V. The enhancement-type nMOS driver transistor has the following parameters:
VDD = 1.1 V
VT0 = 0.52 V
γ = 0 V1/2
λ = 0
µnCox = 216 µA/V2
(a) Determine the required aspect ratio, W/L.
(b) Determine VIL and VIH.
(c) Determine noise margins NML and NMH.
SOLUTION :
(a)When Vout = VOL, Vin = VDD = 1.2V, the driver transistor operates in linear region. Using Eq.(5.12)
Since VOL is small, VOL/EcLn can be ignored. Using (5.17)
Solve for W/L,
(b)When Vin = VIL, driver transistor operates in saturation region.
Since Vin is slightly higher than VT0, Vin-VTO can be ignored. Also vsat=EC/2. Using Eq.(5.21)
Taking derivative with respect to Vin and set
Thus,
When Vin = VIH, driver transistor operates in linear region. Using Eq.(5.27) repeated here :
Differentiating both sides with respect to Vin and set
Plug in back to Eq. (5.27) repeated above to solve for Vout
(c)NML = VIL – VOL = 0.546 – 0.05 = 0.496V
NMH = VOH – VIH = 1.1 – 0.772 = 0.328V
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