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Question :
26. Calculate the linear speed due to the Earth's rotation : 2102154

26. Calculate the linear speed due to the Earth's rotation for a person at the equator of the Earth. The radius of the Earth is 6.40 ´ 10^{6} m.

A. 74.0 m/s

B. 233 m/s

C. 465 m/s

D. 73.0 m/s

27. Calculate the linear speed due to the Earth's rotation for a person at a point on its surface located at 40? N latitude. The radius of the Earth is 6.40 ´ 10^{6} m.

A. 299 m/s

B. 357 m/s

C. 390 m/s

D. 465 m/s

28. A ventilation fan has blades 0.25 m long rotating at 20 rpm. What is the centripetal acceleration of a point on the outer tip of a blade?

A. 1.1 m/s^{2}

B. 0.87 m/s^{2}

C. 0.55 m/s^{2}

D. 0.23 m/s^{2}

29. A 0.30-m-radius automobile tire accelerates from rest at a constant 2.0 rad/s^{2}. What is the centripetal acceleration of a point on the outer edge of the tire after 5.0 s?

A. 300 m/s^{2}

B. 33 m/s^{2}

C. 30 m/s^{2}

D. 3.0 m/s^{2}

30. A 0.40-kg mass, attached to the end of a 0.75-m string, is whirled around in a circular horizontal path. If the maximum tension that the string can withstand is 450 N, then what maximum speed can the mass have if the string is not to break?

A. 370 m/s

B. 22 m/s

C. 19 m/s

D. 29 m/s