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Solve the equation. (x/6) - 4 = 1 A) -30 B) -18 C) 18 D) 30

Question : Solve the equation. (x/6) - 4 = 1 A) -30 B) -18 C) 18 D) 30 : 2151526

MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question.

Solve the equation.

1) (x/6) - 4 = 1

A) -30

B) -18

C) 18

D) 30

2) (x/6) - 3 = -2

A) 6

B) -6

C) -8

D) 8

3) (x/2) + (7x/3) = (x/6)

A) 21

B) 42

C) 6

D) 0

4) (x/4) - (x/9) = 6

A) 24

B) 54

C) 36

D) (216/5)

5) (29/x) = 6 - (1/x)

A) 4

B) (3/14)

C) 5

D) (29/6)

6) (9x/5) + 4 = (1/3)

A) - (55/27)

B) (5/9)

C) - (59/27)

D) (86/27)

7) (5x/7) - 3 = x

A) - (21/2)

B) (2/21)

C) (2/7)

D) (7/5)

8) (x + 3/4) = (x + 4/5)

A) (7/20)

B) (1/20)

C) 1

D) (7/9)

9) (x - 6/2) = (x + 3/6)

A) 3

B) (7/2)

C) (21/2)

D) 8

10) (x/10) - (1/5) = (x + 9/5)

A) -19

B) -10

C) -11

D) -20

11) 1 + (1/x) = (42/x2)

A) 7, -6

B) -7, 6

C) 7, 6

D) - (1/7), (1/6)

12) (8/y + 3) - (4/y - 3) = (4/y2 - 9)

A) √(37)

B) 10

C) 40

D) -10

13) (5 - a/a) + (3/4) = (7/a)

A) -4

B) 8

C) 4

D) -8

14) (2/t) = (t/5t - 12)

A) 0, 36

B) 0

C) 4, 6

D) 0, (24/9)

15) (x/2x + 2) = (-2x/4x + 4) + (2x - 3/x + 1)

A) 3

B) no solution

C) (3/2)

D) -3

16) (1/x + 7) + (5/x + 6) = (-1/x2 + 13x + 42)

A) -7

B) 0

C) no solution

D) 6

Solve the equation for the indicated variable.

17) T = (V/Q) for Q

A) Q = V + T

B) Q = VT

C) Q = (T/V)

D) Q = (V/T)

18) A = (bh/2) for b

A) b = (2A/h)

B) b = (Ah/2)

C) b = (h/2A)

D) b = (A/2h)

19) V = (Bh/3) for h

A) h = (3B/V)

B) h = (B/3V)

C) h = (3V/B)

D) h = (V/3B)

20) A = (h(a + b)/2) for a

A) a = (A - hb/2h)

B) a = (2Ab - h/h)

C) a = (2A - hb/h)

D) a = (hb - 2A/h)

21) I = (nE/nr + R) for n

A) n = IR(Ir - E)

B) n = (R/E - Ir)

C) n = (IR/E - Ir)

D) n = (IR/Ir - E)

22) P = (A/1 + rt) for r

A) r = (P - A/1 + t)

B) r = P - At

C) r = (A - P/Pt)

D) r = (P - 1/At)

23) (P1V1/T1) = (P2V2/T2) for V2

A) V2 = (P1V1T1/P2T2)

B) V2 = (P2V1T2/P1T1)

C) V2 = (P1V1T2/P2T1)

D) V2 = (P1P2T2/V1T1)

24) (1/a) + (1/b) = c for a

A) a = (b/bc - 1)

B) a = (1/c) - b

C) a = bc - (1/b)

D) a = (1/bc)

Solve.

25) Two angles are supplementary if the sum of their measures is 180°. If the measure of one angle is given by ((31x/18))° is over and the measure of its supplement is given by ((7x/9))° is over , find the measures of the two angles.

A) 36°, 144°

B) 72°, 108°

C) 62°, 118°

D) 124°, 56°

26) Two angles are complementary if the sum of their measures is 90°. If the measure of one angle is given by ((720/y))° is over and the measure of its complement is given by ((810/y))° is over , find the measures of the two angles.

A) ((17/2))° is over , ((163/2))° is over

B) (1440/17)°, (1620/17)°

C) 17°, 73°

D) (720/17)°, (810/17)°

Solve the equation.

27) (m + 5/m2 + 5m + 4) - (5/m2 + 2m + 1) = (m - 5/m2 + 5m + 4)

A) 2

B) -2

C) no solution

D) 10

Solution
5 (1 Ratings )

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Algebra 5 Months Ago 34 Views
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