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Solve the equation. Give the solution to three decimal places
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# Question : Solve the equation. Give the solution to three decimal places : 2151567

MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question.

Solve the equation. Give the solution to three decimal places.

1) 5x = 10

A) {0.693}

B) {1.431}

C) {0.699}

D) {2.000}

2) 5x - 1 = 18

A) {2.281}

B) {0.796}

C) {2.796}

D) {4.600}

3) 2-x - 1 = 24

A) {3.485}

B) {-5.585}

C) {-13.000}

D) {3.585}

4) 5-2x - 2 = 17

A) {-1.612}

B) {-2.700}

C) {-1.880}

D) {--0.120}

5) 33x - 1 = 14

A) {1.134}

B) {0.467}

C) {1.889}

D) {0.847}

6) 4x + 1 = 12

A) {2.445}

B) {0.792}

C) {1.792}

D) {2.792}

7) 5x - 1 = 21

A) {3.892}

B) {2.892}

C) {3.900}

D) {1.892}

8) 9-x + 1= 77

A) {8.544}

B) {-0.977}

C) {1.977}

D) {-2.977}

9) 9-x - 1 = 75

A) {-8.486}

B) {-1.965}

C) {-3.965}

D) {-2.965}

10) 43x = 5x + 1

A) {2.161}

B) {1.161}

C) {0.631}

D) {-7.213}

11) 2x + 3 = 10x - 4

A) {5.380}

B) {3.769}

C) {7.015}

D) {3.015}

Solve the equation. Use natural logarithms. When appropriate, give solutions to three decimal places unless otherwise indicated.

12) e-0.16t = 0.16

A) {10.78}

B) {-12.217}

C) {-17.584}

D) {11.454}

13) e0.354x = 18

A) {2.89}

B) {8.165}

C) {1.023}

D) {0.122}

14) e-0.373x = 18

A) {-7.749}

B) {1.078}

C) {2.89}

D) {-0.129}

15) lnex = 22

A) {4.690}

B) {8.094}

C) {22}

D) {3.091}

16) lne5x = 25

A) {125}

B) {30}

C) {20}

D) {5}

17) lne3x = π (Give the exact solution.)

A) {(π/3e)}

B) {3π}

C) {(π/3)}

D) {π - 3}

18) eln5x = eln(4x + 2)

A) {(2/9)}

B) {- (2/9)}

C) {-2}

D) {2}

19) eln(6 - x) = eln(2 + 5x)

A) {1}

B) {2}

C) {(4/3)}

D) {(2/3)}

Solve the equation. Give the exact solution or solutions.

20) logx6 = 3

A) (3)√(6)

B) {2}

C) (6)√(3)

D) ∅

21) log5(9x - 9) = 1

A) {(7/5)}

B) {(14/9)}

C) {5}

D) {(log51 + 9/9)}

22) log(x + 5) = log(2x+ 4)

A) {1}

B) ∅

C) {0}

D) {-1}

23) log(4 + x) - log(x - 4) = log3

A) {-8}

B) {1.5}

C) {8}

D) ∅

24) log3(4x+ 7) = log3(4x+ 4)

A) ∅

B) {4}

C) {0}

D) {3}

25) log2x2 = log2(2x + 15)

A) ∅

B) {5, -3}

C) {5}

D) {-3}

26) log(x - 9) = 1 - logx

A) {10}

B) {-10}

C) {-10, 1}

D) {-1, 10}

27) log(5x - 1) = log1 - log(x - 1)

A) {1, (1/5)}

B) {0, (6/5)}

C) {(6/5)}

D) ∅

28) log9(x - 4) + log9(x - 4) = 1

A) {√(17)}

B) {7}

C) {-7, 7}

D) {-√(17), √(17)}

29) log2(x + 7) + log2(x - 7) = 1

A) {51}

B) {2}

C) {(99/2)}

D) {√(51)}

Solve the problem.

30) Find the amount of money in an account after 2 years if \$2,300 is deposited at 6% annual interest compounded quarterly.

A) \$2,592.47

B) \$2,590.93

C) \$2,584.28

D) \$2,588.67

31) Find the amount of money in an account after 2 years if \$1,400 is deposited at 7% annual interest compounded semiannually.

A) \$1,609.73

B) \$1,602.86

C) \$1,606.53

D) \$1,608.43

32) Find the amount of money in an account after 3 years if \$2,100 is deposited at 7% annual interest compounded monthly.

A) \$2,586.02

B) \$2,581.44

C) \$2,589.14

D) \$2,572.59

33) Find the amount of money in an account after 3 years if \$2,700 is deposited at 5% annual interest compounded annually.

A) \$3,131.17

B) \$3,125.59

C) \$3,135.98

D) \$3,134.04

34) Barry Newman's savings account has a balance of \$2,922. After 14 years, what will the amount of interest be at 5% compounded annually?

A) \$1,461.00

B) \$2,868.36

C) \$2,854.36

D) \$2,863.36

35) Sumi Kato's savings account has a balance of \$89. After 2 years, what will the amount of interest be at 4.5% compounded annually?

A) \$8.19

B) \$17.80

C) \$-2.81

D) \$14.19

36) Noriko invested \$9,000 at 7% compounded semiannually. In how many years will Noriko's investment have quadrupled? Round your answer to the nearest tenth of a year.

A) 7.8 years

B) 19.8 years

C) 2.2 years

D) 20.1 years

37) \$8,500 is invested at 6% compounded quarterly. In how many years will the account have grown to \$14,000? Round your answer to the nearest tenth of a year.

A) 8.6 years

B) 1.1 years

C) 8.4 years

D) 17.6 years

38) What will be the amount in an account with initial principal \$9,000 if interest is compounded continuously at an annual rate of 3.25% for 6 years?

A) \$10,937.80

B) \$9,000.00

C) \$9,297.31

D) \$1,865.37

39) How long would it take \$7,000 to grow to \$35,000 at 6% compounded continuously? Round your answer to the nearest tenth of a year.

A) 27.1 years

B) 27.6 years

C) 29.2 years

D) 26.8 years

## Solution 5 (1 Ratings )

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