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/ Homework Answers / Physics / Question FnetA parallel to incline= F+mAgsin(60) - T FnetA perpendicular to incline=mAgcos(60) FnetB

Question

Question

FnetA parallel to incline= F+mAgsin(60) - T

FnetA perpendicular to incline=mAgcos(60)

FnetB parallel=T - mBgsin(30)

FnetB perpendicular= mBgcos(30)

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