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(5%) Problem 20: A basketball player jumps straight up for a ball. To do this, he lowers his body 0.32 m and then accelerates him through this distance by forcefully straightening his legs. This player leaves the floor with a vertical velocity sufficient to carry 0.895 m above the floor. For this problem, use coordinate system where up is positive. 33% Part (a) Calculate his velocity when he leaves the floor in m/s. Grade Summary 100% Submissions tano cos() Attempts remaining: 20 cotano asino acoso 4 5 6 per attempt) detailed view atano acotano sinh0 1 2 3 ODegrees Radians I give up! Feedback: 0 deduction per feedback. Hints: 0%. deduction per hint. Hints remaining: Part (b) calculate his acceleration, in m/s2, while he is straightening his legs. He goes from zero to the velocity found in part (a) in a distance of 0.32 m. A 33% Part (c) calculate the magnitude of the force he exerts on the floor to do this, in Newtons, given that his mass is 112 kg. 26

## Solution 5 (1 Ratings )

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Physics 2 Months Ago 8 Views  