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Find an equation in slope-intercept form of the line satisfying the specified conditions
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Question : Find an equation in slope-intercept form of the line satisfying the specified conditions : 2143093

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141) y = -4x - 6 A) B) C) D) 142) y = 0.5x + 2 A) B) C) D) 143) y = -2x A) B) C) D) Find an equation in slope-intercept form of the line satisfying the specified conditions.

144) Through ( -7, -5), perpendicular to -9x + 2y = 73

A) y = - 9/2x – 9/2

B) y = - 7/2x – 73/2

C) y = - 2/9x – 59/9

D) y = 2/9x - 59/9

145) Through ( 3, 3), perpendicular to -8x + 7y = -31

A) y = 7/8x – 45/8

B) y = - 7/8x + 45/8

C) y = - 8/7x - 45/7D) y = 7/8x + 31/8

Provide an appropriate response.

146) What is the perpendicular bisector of the segment between A = ( 5, -2) and B = ( 6, 7)? Give the equation in point-slope form.

A) y – 5/2= 1/9((x – 11/2))

B) y – 5/2= - 1/9((x – 11/2))

C) y - 9/2= -9((x – 11/2))

D) y – 5/2= - 1/5((x – 11/2))

147) What is the perpendicular bisector of the segment between C = ( 6, 3) and D = ( 6, -6)?

A) x = 6

B) y = - 9/2

C) y + 3/2= x - 6

D) y = - 3/2

148) What is the perpendicular bisector of the segment between A = ( -8, -6) and B = ( -7, -6)?

A) x = - 15/2

B) y = - 15/2

C) y = -6

D) x = -6

149) What is the equation of the line that is tangent to the circle of radius 7 at (0, 7) and whose center is at the origin?

A) y = x - 7

B) y = 7

C) y = x + 7

D) x = 7

150) What is the equation of the line that is tangent to the circle of radius 8 at (0, -8) and whose center is at the origin?

A) y = -8

B) x = -8

C) y = x - 8

D) y = x + 8

151) What is the equation of the line that is tangent to the circle of diameter 12 at (7,-1 + 2√ 5) and whose center is (3, - 1)?

A) y + 1 = -√5(x - 3)

B) y - ( -1 + 2√5) = -√5 (x - 7)

C) y - ( -1 + 2√5) = - 2/√5(x - 7)

D) y + 1 = - 2/√5 (x - 3)

Solution 5 (1 Ratings )

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Mathematics 1 Day Ago 42 Views