Solution Manual for Beginning and Intermediate Algebra, 7th Edition

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R.1 Fractions Chapter R Prealgebra Review R.1 Fractions Classroom Examples, Now Try Exercises 1. 90 is composite and can be written as N3. The fraction bar represents division. Divide the numerator of the improper fraction by the denominator. 18 5 92 5 42 40 2 Thus, Writing 90 as the product of primes gives us 90 = 2 โ‹… 3 โ‹… 3 โ‹… 5 . N1. 60 is composite and can be written as Writing 60 as the product of primes gives us 60 = 2 โ‹… 2 โ‹… 3 โ‹… 5. 2. (a) 12 3 โ‹… 4 3 4 3 3 = = โ‹… = โ‹…1 = 20 5 โ‹… 4 5 4 5 5 (b) 8 8 1 1 = = = 48 6 โ‹… 8 6 โ‹…1 6 (c) 90 5 โ‹…18 5 5 = = โ‹…1 = 162 9 โ‹…18 9 9 N2. (a) 30 5 โ‹… 6 5 6 5 5 = = โ‹… = โ‹…1 = 42 7 โ‹… 6 7 6 7 7 (b) 10 10 1 1 = = โ‹…= 70 7 โ‹…10 7 โ‹…1 7 (c) 72 3 โ‹… 24 3 3 = = โ‹…1 = 120 5 โ‹… 24 5 5 1 92 2 = 18 . 5 5 4. Multiply the denominator of the fraction by the natural number and then add the numerator to obtain the numerator of the improper fraction. 5 โ‹… 3 = 15 and 15 + 4 = 19 The denominator of the improper fraction is the same as the denominator in the mixed number. 4 19 Thus, 3 = . 5 5 N4. Multiply the denominator of the fraction by the natural number and then add the numerator to obtain the numerator of the improper fraction. 3 โ‹…11 = 33 and 33 + 2 = 35 The denominator of the improper fraction is the same as the denominator in the mixed number. 2 35 Thus, 11 = . 3 3 5. (a) To multiply two fractions, multiply their numerators and then multiply their denominators. Then simplify and write the answer in lowest terms. 5 18 5 โ‹…18 โ‹… = 9 25 9 โ‹… 25 90 = 225 2 โ‹… 45 = 5 โ‹… 45 2 = 5 3. The fraction bar represents division. Divide the numerator of the improper fraction by the denominator. 3 10 37 30 7 37 7 Thus, =3 . 10 10 Copyright ยฉ 2020 Pearson Education, Inc. 2 Chapter R Prealgebra Review (b) To multiply two mixed numbers, first write them as improper fractions. Multiply their numerators and then multiply their denominators. Then simplify and write the answer as a mixed number in lowest terms. 1 3 10 7 3 โ‹…1 = โ‹… 3 4 3 4 10 โ‹… 7 = 3โ‹… 4 2โ‹…5โ‹…7 = 3โ‹… 2 โ‹… 2 5 35 = , or 5 6 6 N5. (a) To multiply two fractions, multiply their numerators and then multiply their denominators. Then simplify and write the answer in lowest terms. 4 5 4โ‹…5 โ‹… = 7 8 7 โ‹…8 20 = 56 5โ‹… 4 = 14 โ‹… 4 5 = 14 (b) To multiply two mixed numbers, first write them as improper fractions. Multiply their numerators and then multiply their denominators. Then simplify and write the answer as a mixed number in lowest terms. 2 2 17 20 3 โ‹…6 = โ‹… 5 3 5 3 17 โ‹… 20 = 5โ‹…3 17 โ‹… 5 โ‹… 4 = 5โ‹…3 68 2 = , or 22 3 3 6. (a) To divide fractions, multiply by the reciprocal of the divisor. 9 3 9 5 รท = โ‹… 10 5 10 3 3โ‹…3โ‹…5 = 2โ‹…5โ‹…3 3 1 = , or 1 2 2 (b) Change both mixed numbers to improper fractions. Then multiply by the reciprocal of the second fraction. 3 1 11 10 2 รท3 = รท 4 3 4 3 11 3 = โ‹… 4 10 33 = 40 N6. (a) To divide fractions, multiply by the reciprocal of the divisor. 2 8 2 9 รท = โ‹… 7 9 7 8 2 โ‹…3โ‹…3 = 7โ‹…2โ‹…4 9 = 28 (b) To divide fractions, multiply by the reciprocal of the divisor. 3 2 15 30 3 รท4 = รท 4 7 4 7 15 7 = โ‹… 4 30 15 โ‹… 7 = 4 โ‹… 2 โ‹…15 7 = 8 7. To find the sum of two fractions having the same denominator, add the numerators and keep the same denominator. 1 5 1+ 5 + = 9 9 9 6 = 9 2โ‹…3 = 3โ‹…3 2 = 3 Copyright ยฉ 2020 Pearson Education, Inc. R.1 Fractions N7. To find the sum of two fractions having the same denominator, add the numerators and keep the same denominator. 1 3 1+ 3 + = 8 8 8 4 = 8 1โ‹… 4 = 2โ‹…4 1 = 2 8. (a) Since 30 = 2 โ‹… 3 โ‹… 5 and 45 = 3 โ‹… 3 โ‹… 5, the least common denominator must have one factor of 2 (from 30), two factors of 3 (from 45), and one factor of 5 (from either 30 or 45), so it is 2 โ‹… 3 โ‹… 3 โ‹… 5 = 90. Write each fraction with a denominator of 90. 7 7 3 21 2 2 2 4 = โ‹… = and = โ‹… = 30 30 3 90 45 45 2 90 Now add. 7 2 21 4 21 + 4 25 + = + = = 30 45 90 90 90 90 25 Write in lowest terms. 90 25 5 โ‹… 5 5 = = 90 18 โ‹… 5 18 (b) Write each mixed number as an improper fraction. 5 1 29 7 + 4 +2 = 6 3 6 3 The least common denominator is 6, so write each fraction with a denominator of 6. 29 7 7 2 14 and = โ‹… = 6 3 3 2 6 Now add. 29 7 29 14 29 + 14 + = + = 6 3 6 6 6 43 1 = , or 7 6 6 N8. (a) Since 12 = 2 โ‹… 2 โ‹… 3 and 8 = 2 โ‹… 2 โ‹… 2, the least common denominator must have three factors of 2 (from 8) and one factor of 3 (from 12), so it is 2 โ‹… 2 โ‹… 2 โ‹… 3 = 24. Write each fraction with a denominator of 24. 3 3 3 9 5 5 2 10 and = โ‹… = = โ‹… = 8 8 3 24 12 12 2 24 3 Now add. 5 3 10 9 10 + 9 19 + = + = = 12 8 24 24 24 24 (b) Write each mixed number as an improper fraction. 1 5 13 45 3 +5 = + 4 8 4 8 The least common denominator is 8, so write each fraction with a denominator of 8. 45 13 13 2 26 and = โ‹… = 8 4 4 2 8 Now add. 13 45 26 45 26 + 45 + = + = 4 8 8 8 8 71 7 = , or 8 8 8 9. (a) Since 10 = 2 โ‹… 5 and 4 = 2 โ‹… 2, the least common denominator is 2 โ‹… 2 โ‹… 5 = 20. Write each fraction with a denominator of 20. 3 3 2 6 1 1 5 5 = โ‹… = and = โ‹… = 10 10 2 20 4 4 5 20 Now subtract. 3 1 6 5 1 โˆ’ = โˆ’ = 10 4 20 20 20 (b) Write each mixed number as an improper fraction. 3 1 27 3 3 โˆ’1 = โˆ’ 8 2 8 2 The least common denominator is 8. Write each fraction with a denominator of 8. 27 8 3 3 4 12 remains unchanged, and = โ‹… = . 2 2 4 8 Now subtract. 27 3 27 12 27 โˆ’ 12 15 7 โˆ’ = โˆ’ = = , or 1 8 2 8 8 8 8 8 N9. (a) Since 11 = 11 and 9 = 3 โ‹… 3, the least common denominator is 3 โ‹… 3 โ‹…11 = 99. Write each fraction with a denominator of 99. 5 5 9 45 2 2 11 22 and = โ‹… = = โ‹… = 11 11 9 99 9 9 11 99 Now subtract. 5 2 45 22 23 โˆ’ = โˆ’ = 11 9 99 99 99 Copyright ยฉ 2020 Pearson Education, Inc. 4 Chapter R Prealgebra Review (b) Write each mixed number as an improper fraction. 1 5 13 17 4 โˆ’2 = โˆ’ 3 6 3 6 The least common denominator is 6. Write 17 each fraction with a denominator of 6. 6 13 13 2 26 remains unchanged, and = โ‹… = . 3 3 2 6 Now subtract. 13 17 26 17 26 โˆ’ 17 9 โˆ’ = โˆ’ = = 3 6 6 6 6 6 Now reduce. 9 3โ‹…3 3 1 = = , or 1 6 2โ‹…3 2 2 10. To find out how many yards of fabric Jen should buy, add the lengths needed for each piece to obtain the total length. The common denominator is 12. 1 2 1 3 8 6 17 1 +1 + 2 = 1 +1 + 2 = 4 4 3 2 12 12 12 12 17 5 Because = 1 , we have 12 12 17 5 5 5 yd 4 = 4 + 1 = 5 . Jen should buy 5 12 12 12 12 of fabric. N10. To find out how long each piece must be, divide the total length by the number of pieces. 1 21 4 21 1 21 5 10 รท 4 = รท = โ‹… = , or 2 2 2 1 2 4 8 8 5 Each piece should be 2 feet long. 8 11. (a) In the circle graph, the sector for Other is the second largest, so Other had the second 23 . largest share of Internet users, 100 (b) The total number of Internet users, 3900 million, can be rounded to 4000 million (or 1 by 4000. 4 billion). Multiply 10 1 โ‹… 4000 = 400 million 10 N11. (a) In the circle graph, the sector for Africa is the smallest, so Africa had the least number of Internet users. (b) The total number of Internet users, 3900 million, can be rounded to 4000 million (or 1 4 billion). Multiply by 4000. 2 1 โ‹… 4000 = 2000 million, or 2 billion 2 (c) Multiply the fraction from the graph for Asia by the actual number of users. 1 โ‹… 3900 = 1950 million, or 1.95 billion 2 Exercises 1. True; the number above the fraction bar is called the numerator and the number below the fraction bar is called the denominator. 2. True; 5 divides the 31 six times with a 31 1 remainder of one, so = 6 . 5 5 3. False; this is an improper fraction. Its value is 1. 4. False; the number 1 is neither prime nor composite. 13 can be written in lowest 39 1 13 13 โ‹…1 1 = = . terms as since 3 39 13 โ‹… 3 3 5. False; the fraction 6. False; the reciprocal of 6 2 1 = 3 is = . 2 6 3 7. False; product refers to multiplication, so the product of 10 and 2 is 20. The sum of 10 and 2 is 12. 8. False; difference refers to subtraction, so the difference between 10 and 2 is 8. The quotient of 10 and 2 is 5. 9. 16 2 โ‹… 8 2 = = 24 3 โ‹… 8 3 Therefore, C is correct. (c) Multiply the fraction from the graph for Africa by the actual number of users. 1 โ‹… 3900 = 390 million 10 Copyright ยฉ 2020 Pearson Education, Inc. R.1 Fractions 10. Simplify each fraction to find which are equal 5 to . 9 15 3 โ‹… 5 5 = = 27 3 โ‹… 9 9 30 6 โ‹… 5 5 = = 54 6 โ‹… 9 9 40 2 โ‹… 20 20 = = 74 2 โ‹… 37 37 55 11 โ‹… 5 5 = = 99 11 โ‹… 9 9 Therefore, C is correct. p and r must be q s a multiple of both denominators, q and s. Such a number is q โ‹… s. Therefore, A is correct. 11. A common denominator for 12. We need to multiply 8 by 3 to get 24 in the denominator, so we must multiply 5 by 3 as well. 5 5 โ‹… 3 15 = = 8 8 โ‹… 3 24 Therefore, B is correct. 13. Since 19 has only itself and 1 as factors, it is a prime number. 14. Since 31 has only itself and 1 as factors, it is a prime number. 15. 30 = 2 โ‹…15 = 2 โ‹…3โ‹…5 Since 30 has factors other than itself and 1, it is a composite number. 16. 50 = 2 โ‹… 25 = 2 โ‹… 5 โ‹… 5, so 50 is a composite number. 5 19. As stated in the text, the number 1 is neither prime nor composite, by agreement. 20. The number 0 is not a natural number, so it is neither prime nor composite. 21. 57 = 3 โ‹…19, so 57 is a composite number. 22. 51 = 3 โ‹…17, so 51 is a composite number. 23. Since 79 has only itself and 1 as factors, it is a prime number. 24. Since 83 has only itself and 1 as factors, it is a prime number. 25. 124 = 2 โ‹… 62 = 2 โ‹… 2 โ‹… 31, so 124 is a composite number. 26. 138 = 2 โ‹… 69 = 2 โ‹… 3 โ‹… 23, so 138 is a composite number. 27. 500 = 2 โ‹… 250 = 2 โ‹… 2 โ‹…125 = 2 โ‹… 2 โ‹… 5 โ‹… 25 = 2 โ‹… 2 โ‹… 5 โ‹… 5 โ‹… 5, so 500 is a composite number. 28. 700 = 2 โ‹… 350 = 2 โ‹… 2 โ‹…175 = 2 โ‹… 2 โ‹… 5 โ‹… 35 = 2 โ‹… 2 โ‹… 5 โ‹… 5 โ‹… 7, so 700 is a composite number. 29. 3458 = 2 โ‹…1729 = 2 โ‹… 7 โ‹… 247 = 2 โ‹… 7 โ‹…13 โ‹…19 Since 3458 has factors other than itself and 1, it is a composite number. 17. 64 = 2 โ‹… 32 = 2 โ‹… 2 โ‹…16 = 2 โ‹… 2 โ‹… 2 โ‹…8 = 2โ‹…2โ‹…2โ‹…2โ‹…4 = 2โ‹…2โ‹…2โ‹…2โ‹…2โ‹…2 Since 64 has factors other than itself and 1, it is a composite number. 30. 1025 = 5โ‹… 205 = 5 โ‹… 5 โ‹… 41 Since 1025 has factors other than itself and 1, it is a composite number. 31. 8 1โ‹… 8 1 8 1 1 = = โ‹… = โ‹…1 = 16 2 โ‹… 8 2 8 2 2 18. 81 = 3 โ‹… 27 = 3โ‹…3โ‹…9 = 3โ‹…3โ‹…3โ‹…3 Since 81 has factors other than itself and 1, it is a composite number. 32. 4 1โ‹… 4 1 4 1 1 = = โ‹… = โ‹…1 = 12 3 โ‹… 4 3 4 3 3 33. 15 3 โ‹… 5 3 5 5 5 = = โ‹… = 1โ‹… = 18 3 โ‹… 6 3 6 6 6 Copyright ยฉ 2020 Pearson Education, Inc. 6 Chapter R Prealgebra Review 34. 16 4 โ‹… 4 4 4 4 4 = = โ‹… = โ‹…1 = 20 5 โ‹… 4 5 4 5 5 35. 90 3 โ‹… 30 3 30 3 3 = = โ‹… = โ‹…1 = 150 5 โ‹… 30 5 30 5 5 100 5 โ‹… 20 5 20 5 5 36. = = โ‹… = โ‹…1 = 140 7 โ‹… 20 7 20 7 7 18 1 โ‹…18 1 18 1 1 37. = = โ‹… = โ‹…1 = 90 5 โ‹…18 5 18 5 5 38. 16 1 โ‹…16 1 16 1 1 = = โ‹… = โ‹…1 = 64 4 โ‹…16 4 16 4 4 39. 144 6 โ‹… 24 6 24 6 6 = = โ‹… = โ‹…1 = 120 5 โ‹… 24 5 24 5 5 40. 132 12 โ‹…11 12 11 12 12 = = โ‹… = โ‹…1 = 77 7 โ‹…11 7 11 7 7 1 41. 7 12 7 5 12 5 =1 . Therefore, 7 7 1 42. 9 16 9 7 Therefore, 16 7 =1 . 9 9 6 43. 12 77 72 5 Therefore, 77 5 =6 . 12 12 6 44. 15 101 90 11 Therefore, 101 11 =6 . 15 15 7 45. 11 83 77 6 Therefore, 83 6 =7 . 11 11 5 46. 13 67 65 2 Therefore, 67 2 =5 . 13 13 47. Multiply the denominator of the fraction by the natural number and then add the numerator to obtain the numerator of the improper fraction. 5 โ‹… 2 = 10 and 10 + 3 = 13 The denominator of the improper fraction is the same as the denominator in the mixed number. 3 13 Thus, 2 = . 5 5 48. Multiply the denominator of the fraction by the natural number and then add the numerator to obtain the numerator of the improper fraction. 7 โ‹… 5 = 35 and 35 + 6 = 41 The denominator of the improper fraction is the same as the denominator in the mixed number. 6 41 Thus, 5 = . 7 7 49. Multiply the denominator of the fraction by the natural number and then add the numerator to obtain the numerator of the improper fraction. 8 โ‹…10 = 80 and 80 + 3 = 83 The denominator of the improper fraction is the same as the denominator in the mixed number. 3 83 Thus, 10 = . 8 8 50. Multiply the denominator of the fraction by the natural number and then add the numerator to obtain the numerator of the improper fraction. 3 โ‹…12 = 36 and 36 + 2 = 38 The denominator of the improper fraction is the same as the denominator in the mixed number. 2 38 Thus, 12 = . 3 3 Copyright ยฉ 2020 Pearson Education, Inc. R.1 Fractions 51. Multiply the denominator of the fraction by the natural number and then add the numerator to obtain the numerator of the improper fraction. 5 โ‹…10 = 50 and 50 + 1 = 51 The denominator of the improper fraction is the same as the denominator in the mixed number. 1 51 Thus, 10 = . 5 5 52. Multiply the denominator of the fraction by the natural number and then add the numerator to obtain the numerator of the improper fraction. 6 โ‹…18 = 108 and 108 + 1 = 109 The denominator of the improper fraction is the same as the denominator in the mixed number. 1 109 Thus, 18 = . 6 6 53. 4 6 4 โ‹… 6 24 โ‹… = = 5 7 5 โ‹… 7 35 54. 5 2 5 โ‹… 2 10 โ‹… = = 9 7 9 โ‹… 7 63 55. 2 3 2โ‹…3 6 1โ‹… 6 1 โ‹… = = = = 15 8 15 โ‹… 8 120 20 โ‹… 6 20 56. 3 5 3โ‹…5 15 1 โ‹…15 1 โ‹… = = = = 20 21 20 โ‹… 21 420 28 โ‹…15 28 57. 1 12 1 โ‹…12 1 โ‹… 2 โ‹… 6 6 โ‹… = = = 10 5 10 โ‹… 5 2 โ‹… 5 โ‹… 5 25 58. 1 10 1 โ‹…10 1 โ‹… 2 โ‹… 5 5 โ‹… = = = 8 7 8 โ‹… 7 2 โ‹… 4 โ‹… 7 28 59. 60. 15 8 15 โ‹… 8 โ‹… = 4 25 4 โ‹… 25 3โ‹…5โ‹… 4โ‹… 2 = 4โ‹…5โ‹…5 3โ‹… 2 = 5 6 1 = , or 1 5 5 21 4 21 โ‹… 4 โ‹… = 8 7 8โ‹…7 3โ‹… 7 โ‹… 4 = 4โ‹…2โ‹…7 3 1 = , or 1 2 2 61. 21 โ‹… 62. 36 โ‹… 3 21 3 = โ‹… 7 1 7 21 โ‹… 3 = 1โ‹… 7 3โ‹… 7 โ‹…3 = 1โ‹… 7 3โ‹…3 = =9 1 4 36 4 = โ‹… 9 1 9 36 โ‹… 4 = 1โ‹… 9 4โ‹…9โ‹… 4 = 1โ‹… 9 4โ‹…4 = = 16 1 63. Change both mixed numbers to improper fractions. 1 2 13 5 3 โ‹…1 = โ‹… 4 3 4 3 13 โ‹… 5 = 4โ‹…3 65 5 = , or 5 12 12 64. Change both mixed numbers to improper fractions. 2 3 8 8 2 โ‹…1 = โ‹… 3 5 3 5 8โ‹…8 = 3โ‹…5 64 4 = , or 4 15 15 65. Change both mixed numbers to improper fractions. 3 1 19 16 2 โ‹…3 = โ‹… 8 5 8 5 19 โ‹…16 = 8โ‹…5 19 โ‹… 2 โ‹… 8 = 8โ‹…5 38 3 = , or 7 5 5 Copyright ยฉ 2020 Pearson Education, Inc. 7 8 Chapter R Prealgebra Review 66. Change both mixed numbers to improper fractions. 3 1 18 43 3 โ‹…7 = โ‹… 5 6 5 6 18 โ‹… 43 = 5โ‹…6 3 โ‹… 6 โ‹… 43 = 5โ‹…6 3 โ‹… 43 = 5 129 4 = , or 25 5 5 67. Change both numbers to improper fractions. 1 5 21 5โ‹…2 = โ‹… 10 1 10 5 โ‹… 21 = 1 โ‹…10 5 โ‹… 21 = 1โ‹… 2 โ‹… 5 21 = 1โ‹… 2 1 21 = , or 10 2 2 68. Change both numbers to improper fractions. 2 3 38 3โ‹… 4 = โ‹… 9 1 9 3 โ‹… 38 = 1โ‹… 9 3 โ‹… 38 = 1โ‹… 3 โ‹… 3 38 = 1โ‹… 3 38 2 = , or 12 3 3 69. To divide fractions, multiply by the reciprocal of the divisor. 7 3 7 2 รท = โ‹… 9 2 9 3 7โ‹…2 = 9โ‹…3 14 = 27 70. To divide fractions, multiply by the reciprocal of the divisor. 6 5 6 4 รท = โ‹… 11 4 11 5 6โ‹…4 = 11 โ‹… 5 24 = 55 71. To divide fractions, multiply by the reciprocal of the divisor. 5 3 5 8 รท = โ‹… 4 8 4 3 5โ‹…8 = 4โ‹…3 5โ‹… 4โ‹… 2 = 4โ‹…3 5โ‹… 2 = 3 10 1 = , or 3 3 3 72. To divide fractions, multiply by the reciprocal of the divisor. 7 3 7 10 รท = โ‹… 5 10 5 3 7 โ‹…10 = 5โ‹…3 7 โ‹… 2โ‹…5 = 5โ‹…3 14 2 = , or 4 3 3 73. To divide fractions, multiply by the reciprocal of the divisor. 32 8 32 15 รท = โ‹… 5 15 5 8 32 โ‹…15 = 5โ‹…8 8โ‹… 4 โ‹…3โ‹…5 = 1โ‹… 5 โ‹… 8 4โ‹…3 = = 12 1 Copyright ยฉ 2020 Pearson Education, Inc. R.1 Fractions 74. To divide fractions, multiply by the reciprocal of the divisor. 24 6 24 21 รท = โ‹… 7 21 7 6 24 โ‹… 21 = 7โ‹…6 4 โ‹… 6 โ‹…3โ‹… 7 = 1โ‹… 7 โ‹… 6 4โ‹…3 = = 12 1 78. To divide fractions, multiply by the reciprocal of the divisor. 4 8 9 8รท = โ‹… 9 1 4 8โ‹…9 = 1โ‹… 4 2โ‹… 4โ‹…9 = 1โ‹… 4 2โ‹…9 = = 18 1 75. To divide fractions, multiply by the reciprocal of the divisor. 3 3 1 รท 12 = โ‹… 4 4 12 3 โ‹…1 = 4 โ‹…12 3 โ‹…1 = 4 โ‹…3โ‹… 4 1 1 = = 4 โ‹… 4 16 79. Change the first number to an improper fraction, and then multiply by the reciprocal of the divisor. 3 3 27 3 รท 6 รท = 4 8 4 8 27 8 = โ‹… 4 3 27 โ‹… 8 = 4โ‹…3 3โ‹…9 โ‹… 2 โ‹… 4 = 4โ‹…3 9โ‹…2 = = 18 1 76. To divide fractions, multiply by the reciprocal of the divisor. 2 2 1 รท 30 = โ‹… 5 5 30 2 โ‹…1 = 5 โ‹… 30 2 โ‹…1 = 5 โ‹… 2 โ‹…15 1 1 = = 5 โ‹…15 75 77. To divide fractions, multiply by the reciprocal of the divisor. 3 6 5 6รท = โ‹… 5 1 3 6โ‹…5 = 1โ‹… 3 2 โ‹…3โ‹…5 = 1โ‹… 3 2โ‹…5 = = 10 1 9 80. Change the first number to an improper fraction, and then multiply by the reciprocal of the divisor. 3 7 28 7 รท 5 รท = 5 10 5 10 28 10 = โ‹… 5 7 28 โ‹…10 = 5โ‹…7 4โ‹…7โ‹…2โ‹…5 = 5โ‹…7 4โ‹…2 = =8 1 81. Change both mixed numbers to improper fractions, and then multiply by the reciprocal of the divisor. 1 5 5 12 2 รท1 = รท 2 7 2 7 5 7 = โ‹… 2 12 5โ‹…7 = 2 โ‹…12 35 11 , or 1 = 24 24 Copyright ยฉ 2020 Pearson Education, Inc. 10 Chapter R Prealgebra Review 82. Change both mixed numbers to improper fractions, and then multiply by the reciprocal of the divisor. 2 2 20 7 รท 2 รท1 = 9 5 9 5 20 5 = โ‹… 9 7 20 โ‹… 5 = 9โ‹…7 100 37 = , or 1 63 63 83. Change both mixed numbers to improper fractions, and then multiply by the reciprocal of the divisor. 5 15 21 47 2 รท1 = รท 8 32 8 32 21 32 = โ‹… 8 47 21 โ‹… 32 = 8 โ‹… 47 21 โ‹… 8 โ‹… 4 = 8 โ‹… 47 21 โ‹… 4 = 47 84 37 = , or 1 47 47 84. Change both mixed numbers to improper fractions, and then multiply by the reciprocal of the divisor. 3 4 23 9 รท 2 รท1 = 10 5 10 5 23 5 = โ‹… 10 9 23 โ‹… 5 = 2โ‹…5โ‹…9 23 5 = , or 1 18 8 85. 7 4 7 + 4 11 + = = 15 15 15 15 86. 2 5 2+5 7 + = = 9 9 9 9 87. 88. 7 1 7 +1 + = 12 12 12 8 = 12 2โ‹…4 = 3โ‹… 4 2 = 3 3 5 3+5 8 1 + = = = 16 16 16 16 2 89. Since 9 = 3 โ‹… 3, and 3 is prime, the LCD (least common denominator) is 3 โ‹… 3 = 9. 1 1 3 3 = โ‹… = 3 3 3 9 Now add the two fractions with the same denominator. 5 1 5 3 8 + = + = 9 3 9 9 9 4 1 and , first find the LCD. Since 15 5 15 = 3 โ‹… 5 and 5 is prime, the LCD is 15. 4 1 4 1 3 + = + โ‹… 15 5 15 5 3 4 3 = + 15 15 4+3 = 15 7 = 15 90. To add 91. Since 8 = 2 โ‹… 2 โ‹… 2 and 6 = 2 โ‹… 3, the LCD is 2 โ‹… 2 โ‹… 2 โ‹… 3 = 24. 3 3 3 9 5 5 4 20 = โ‹… = and = โ‹… = 8 8 3 24 6 6 4 24 Now add fractions with the same denominator. 3 5 9 20 29 5 + = + = , or 1 24 8 6 24 24 24 92. Since 6 = 2 โ‹… 3 and 9 = 3 โ‹… 3, the LCD is 2 โ‹… 3 โ‹… 3 = 18. 5 5 3 15 2 2 2 4 and = โ‹… = = โ‹… = 6 6 3 18 9 9 2 18 Now add fractions with the same denominator. 5 2 15 4 19 1 + = + = , or 1 6 9 18 18 18 18 Copyright ยฉ 2020 Pearson Education, Inc. R.1 Fractions 11 93. Since 9 = 3 โ‹… 3 and 16 = 4 โ‹… 4, the LCD is 3 โ‹… 3 โ‹… 4 โ‹… 4 = 144. 5 5 16 80 3 3 9 27 = โ‹… = = โ‹… = and 9 9 16 144 16 16 9 144 Now add fractions with the same denominator. 5 3 80 27 107 + = + = 9 16 144 144 144 94. Since 4 = 2 โ‹… 2 and 25 = 5 โ‹… 5, the LCD is 2 โ‹… 2 โ‹… 5 โ‹… 5 = 100. 3 3 25 75 6 6 4 24 and = โ‹… = = โ‹… = 4 4 25 100 25 25 4 100 Now add fractions with the same denominator. 3 6 75 24 99 + = + = 4 25 100 100 100 95. 1 1 24 1 25 + = 3 = 3+ = 8 8 8 8 8 1 1 8 1 9 2 = 2+ = + = 4 4 4 4 4 1 1 25 9 + 3 +2 = 8 4 8 4 Since 8 = 2 โ‹… 2 โ‹… 2 and 4 = 2 โ‹… 2, the LCD is 2 โ‹… 2 โ‹… 2 or 8. 1 1 25 9 2 + โ‹… 3 +2 = 8 4 8 4 2 25 18 = + 8 8 43 3 = , or 5 8 8 2 2 12 2 14 = 4+ = + = 3 3 3 3 3 1 1 12 1 13 2 = 2+ = + = 6 6 6 6 6 Since 6 = 2 โ‹… 3, the LCD is 6. 2 1 14 2 13 4 +2 = โ‹… + 3 6 3 2 6 28 13 = + 6 6 41 5 = , or 6 6 6 Since 4 = 2 โ‹… 2, and 5 is prime, the LCD is 2 โ‹… 2 โ‹… 5 = 20. 1 4 13 5 9 4 3 +1 = โ‹… + โ‹… 4 5 4 5 5 4 65 36 = + 20 20 101 1 = , or 5 20 20 1 3 and 1 , first change to improper 3 4 fractions then find the LCD, which is 12. 3 1 23 4 5 +1 = + 4 3 4 3 23 3 4 4 = โ‹… + โ‹… 4 3 3 4 69 16 = + 12 12 85 1 = , or 7 12 12 98. To add 5 99. 7 2 7โˆ’2 5 โˆ’ = = 9 9 9 9 100. 8 3 8โˆ’3 5 โˆ’ = = 11 11 11 11 101. 96. 4 1 1 12 1 13 97. 3 = 3 + = + = 4 4 4 4 4 4 4 5 4 9 1 = 1+ = + = 5 5 5 5 5 102. 13 3 13 โˆ’ 3 โˆ’ = 15 15 15 10 = 15 2โ‹…5 2 = = 3โ‹…5 3 11 3 11 โˆ’ 3 โˆ’ = 12 12 12 8 = 12 2โ‹…4 2 = = 3โ‹… 4 3 103. Since 12 = 4 โ‹… 3 (12 is a multiple of 3), the LCD is 12. 1 4 4 โ‹… = 3 4 12 Now subtract fractions with the same denominator. 7 1 7 4 3 1โ‹… 3 1 โˆ’ = โˆ’ = = = 12 3 12 12 12 4 โ‹… 3 4 Copyright ยฉ 2020 Pearson Education, Inc. 12 Chapter R Prealgebra Review 104. Since 6 = 3 โ‹… 2 (6 is a multiple of 2), the LCD is 6. 1 3 3 โ‹… = 2 3 6 Now subtract fractions with the same denominator. 5 1 5 3 2 1โ‹… 2 1 โˆ’ = โˆ’ = = = 6 2 6 6 6 3โ‹… 2 3 105. Since 12 = 2 โ‹… 2 โ‹… 3 and 9 = 3 โ‹… 3, the LCD is 2 โ‹… 2 โ‹… 3 โ‹… 3 = 36. 7 7 3 21 1 4 4 = โ‹… = and โ‹… = 12 12 3 36 9 4 36 Now subtract fractions with the same denominator. 7 1 21 4 17 โˆ’ = โˆ’ = 12 9 36 36 36 106. 11 1 11 3 1 4 The LCD of 12 โˆ’ = โ‹… โˆ’ โ‹… 16 12 16 3 12 4 and 16 is 48. 33 4 = โˆ’ 48 48 29 = 48 3 3 16 3 19 = 4+ = + = 4 4 4 4 4 2 2 5 2 7 1 = 1+ = + = 5 5 5 5 5 Since 4 = 2 โ‹… 2, and 5 is prime, the LCD is 2 โ‹… 2 โ‹… 5 = 20. 3 2 19 5 7 4 4 โˆ’1 = โ‹… โˆ’ โ‹… 4 5 4 5 5 4 95 28 = โˆ’ 20 20 67 7 = , or 3 20 20 107. 4 108. Change both numbers to improper fractions then add, using 45 as the common denominator. 4 4 19 13 3 โˆ’1 = โˆ’ 5 9 5 9 19 9 13 5 = โ‹… โˆ’ โ‹… 5 9 9 5 171 65 = โˆ’ 45 45 106 16 , or 2 = 45 45 1 1 24 1 25 = 6+ = + = 4 4 4 4 4 1 1 15 1 16 5 = 5+ = + = 3 3 3 3 3 Since 4 = 2 โ‹… 2, and 3 is prime, the LCD is 2 โ‹… 2 โ‹… 3 = 12. 1 1 25 16 6 โˆ’5 = โˆ’ 4 3 4 3 25 3 16 4 = โ‹… โˆ’ โ‹… 4 3 3 4 75 64 = โˆ’ 12 12 11 = 12 109. 6 110. 1 1 15 1 16 5 = 5+ = + = 3 3 3 3 3 1 1 8 1 9 4 = 4+ = + = 2 2 2 2 2 2 and 3 are prime, so the LCD is 2 โ‹… 3 = 6. 1 1 16 2 9 3 5 โˆ’4 = โ‹… โˆ’ โ‹… 3 2 3 2 2 3 32 27 = โˆ’ 6 6 5 = 6 2 2 72 2 74 = 8+ = + = 9 9 9 9 9 2 2 12 2 14 4 = 4+ = + = 3 3 3 3 3 Since 9 = 3 โ‹… 3, and 3 is prime, the LCD is 3 โ‹… 3 = 9. 2 2 74 14 3 8 โˆ’4 = โˆ’ โ‹… 9 3 9 3 3 74 42 = โˆ’ 9 9 32 5 = , or 3 9 9 111. 8 Copyright ยฉ 2020 Pearson Education, Inc. R.1 Fractions 13 5 5 84 5 89 = 7+ = + = 12 12 12 12 12 5 5 24 5 29 4 = 4+ = + = 6 6 6 6 6 Since 12 = 2 โ‹… 2 โ‹… 3 and 6 = 2 โ‹… 3, the LCD is 2 โ‹… 2 โ‹… 3 = 12. 5 5 89 29 2 7 โˆ’4 = โˆ’ โ‹… 12 6 12 6 2 89 58 = โˆ’ 12 12 31 7 = , or 2 12 12 112. 7 113. Observe that there are 24 dots in the entire figure, 6 dots in the triangle, 12 dots in the rectangle, and 2 dots in the overlapping region. (a) 12 1 = of all the dots are in the rectangle. 24 2 (b) 6 1 = of all the dots are in the triangle. 24 4 (c) (d) 2 1 = of the dots in the triangle are in the 6 3 overlapping region. 2 1 = of the dots in the rectangle are in 12 6 the overlapping region. 1 of 36, so Maureen got a hit in 3 1 exactly of her at-bats. 3 114. (a) 12 is 1 of 11, so Chase got a 2 1 hit in just less than of his at-bats. 2 (b) 5 is a little less than 1 of 11, so Chase got 10 1 a home run in just less than of his at10 bats. (c) 1 is a little less than 1 1 of 16, and 10 is of 20, so Joe and 2 2 1 Greg each got hits of the time they were 2 at bat. (e) 8 is 115. Multiply the number of cups of water per serving by the number of servings. 3 3 8 โ‹…8 = โ‹… 4 4 1 3โ‹…8 = 4 โ‹…1 24 = 4 = 6 cups For 8 microwave servings, 6 cups of water will be needed. 1 2 tsp, or 4 8 1 tsp, of salt. Six stove-top servings require 2 4 tsp, or tsp, of salt. Five is halfway between 4 8 3 2 4 and 6, and is halfway between and . 8 8 8 Therefore, 5 stove-top servings would require 3 tsp of salt. 8 116. Four stove-top servings require 117. The difference in length is found by subtracting. 1 1 13 17 3 โˆ’2 = โˆ’ 4 8 4 8 13 2 17 = โ‹… โˆ’ LCD = 8 4 2 8 26 17 = โˆ’ 8 8 9 1 = , or 1 8 8 1 The difference is 1 inches. 8 1 of 40, so Christine 4 1 got a hit in just less than of her at-bats. 4 (d) 9 is a little less than Copyright ยฉ 2020 Pearson Education, Inc. 14 Chapter R Prealgebra Review 118. The difference in length is found by subtracting. 1 4 17 4โˆ’2 = โˆ’ 8 1 8 4 8 17 = โ‹… โˆ’ LCD = 8 1 8 8 32 17 = โˆ’ 8 8 15 7 = , or 1 8 8 7 The difference is 1 inches. 8 119. The difference between the two measures is found by subtracting, using 16 as the LCD. 3 3 3 4 3 โˆ’ = โ‹… โˆ’ 4 16 4 4 16 12 3 = โˆ’ 16 16 12 โˆ’ 3 = 16 9 = 16 9 The difference is inch. 16 120. The difference between the two measures is found by subtracting, using 16 as a common denominator. 9 3 9 3 2 โˆ’ = โˆ’ โ‹… 16 8 16 8 2 9 6 = โˆ’ 16 16 9โˆ’6 = 16 3 = 16 3 inch. The difference is 16 121. The perimeter is the sum of the measures of the 5 sides. 3 1 7 5 196 + 98 + 146 + 100 + 76 4 2 8 8 6 4 7 5 = 196 + 98 + 146 + 100 + 76 8 8 8 8 6+4+7+5 = 196 + 98 + 146 + 100 + 76 + 8 22 ๏ƒฆ 22 6 3๏ƒถ = 616 + =2 =2 ๏ƒท ๏ƒง 8 ๏ƒจ 8 8 4๏ƒธ 3 = 618 feet 4 3 The perimeter is 618 feet. 4 122. To find the perimeter of a triangle, add the lengths of the three sides. 1 1 1 2 4 1 5 + 7 + 10 = 5 + 7 + 10 4 2 8 8 8 8 7 = 22 8 7 The perimeter of the triangle is 22 feet. 8 123. Divide the total board length by 3. 5 125 3 15 รท 3 = รท 8 8 1 125 1 = โ‹… 8 3 125 โ‹…1 = 8โ‹…3 125 5 = , or 5 24 24 The length of each of the three pieces must be 5 inches. 5 24 124. Divide the total amount of tomato sauce by the number of servings. 1 7 7 7 1 7 โ‹…1 1 2 รท7 = รท = โ‹… = = 3 3 1 3 7 3โ‹… 7 3 1 For 1 serving of barbecue sauce, cup of 3 tomato sauce is needed. Copyright ยฉ 2020 Pearson Education, Inc. R.1 Fractions 15 125. To find the number of cakes the caterer can 1 3 make, divide 15 by 1 . 2 4 1 3 31 7 15 รท 1 = รท 2 4 2 4 31 4 = โ‹… 2 7 31 โ‹… 2 โ‹… 2 = 2โ‹…7 62 6 = , or 8 7 7 There is not quite enough sugar for 9 cakes. The caterer can make 8 cakes with some sugar left over. 126. Divide the total amount of fabric by the amount of fabric needed to cover one chair. 2 1 71 9 23 รท 2 = รท 4 3 4 3 71 4 = โ‹… 3 9 71 โ‹… 4 = 3โ‹…9 284 14 , or 10 = 27 27 Kyla can cover 10 chairs. There will be some fabric left over. 127. Multiply the amount of fabric it takes to make one costume by the number of costumes. 3 19 7 2 โ‹…7 = โ‹… 8 8 1 19 โ‹… 7 = 8 โ‹…1 133 5 , or 16 yd = 8 8 5 For 7 costumes, 16 yards of fabric would be 8 needed. 128. Multiply the amount of sugar for one batch times the number of batches. 2 8 4 2 โ‹…4 = โ‹… 3 3 1 8โ‹… 4 = 3 โ‹…1 32 2 = , or 10 3 3 2 10 cups of sugar are required to make four 3 batches of cookies. 129. Subtract the heights to find the difference. 1 1 21 57 10 โˆ’ 7 = โˆ’ 2 8 2 8 21 4 57 = โ‹… โˆ’ LCD = 8 2 4 8 84 57 = โˆ’ 8 8 27 3 = , or 3 8 8 3 The difference in heights is 3 inches. 8 3 11 from using 16 as the LCD. 8 16 11 3 11 3 2 โˆ’ = โˆ’ โ‹… 16 8 16 8 2 11 6 = โˆ’ 16 16 5 = 16 3 5 11 inch smaller than inch. Thus, inch is 8 16 16 130. Subtract 11 10 1 can be rounded to = . 100 100 10 Multiply by the total number of foreign-born people in the U.S., approximately 40 million. 1 1 40 4 โ‹…10 4 โ‹… 40 = โ‹… = = = 4, 10 10 1 1 โ‹…10 1 There were approximately 4 million (or 4,000,000) foreign-born people in the U.S. who were born in Europe. For the actual number: 2 11 11 40 11 โ‹… 2 โ‹… 20 22 โ‹… 40 = โ‹… = = , or 4 5 100 100 1 5 โ‹… 20 โ‹…1 5 The actual number who were born in Europe 2 was 4 million (or 4,400,000) people. 5 131. A share of 132. Multiply the fraction representing the U.S. foreign-born population from Latin America, 13 , by the total number of foreign-born people 25 in the U.S., approximately 40 million. 4 13 13 40 13 โ‹… 5 โ‹… 8 104 โ‹… 40 = โ‹… = = , or 20 5 25 25 1 5 โ‹… 5 โ‹…1 5 4 There were approximately 20 million (or 5 20,800,000) foreign-born people in the U.S. who were born in Latin America. Copyright ยฉ 2020 Pearson Education, Inc. 16 Chapter R Prealgebra Review 133. The sum of the fractions representing the U.S. foreign-born population from Latin America, Asia, or Europe is 13 29 11 13 4 29 11 + + = โ‹… + + 25 100 100 25 4 100 100 52 + 29 + 11 = 100 92 = 100 23 โ‹… 4 = 25 โ‹… 4 23 = . 25 So the fraction representing the U.S. foreignborn population from other regions is 23 25 23 1โˆ’ = โˆ’ 25 25 25 2 = . 25 134. The sum of the fractions representing the U.S. foreign-born population from Latin America or Asia is 13 29 13 4 29 + = โ‹… + 25 100 25 4 100 52 + 29 = 100 81 = . 100 14 1 98 135. Estimate each fraction. is about , is 26 2 99 100 90 is about 2, is about 3, and about 1, 51 31 13 1 is about . 27 2 Therefore, the sum is approximately 1 1 + 1 + 2 + 3 + = 7. 2 2 The correct choice is C. 202 99 is about 4, is 50 100 21 75 1 is about , and is about 2. about 1, 40 36 2 Therefore, the product is approximately 1 4 โ‹…1 โ‹… โ‹… 2 = 4 2 The correct choice is B. R.2 Decimals and Percents Classroom Examples, Now Try Exercises 1. (a) 0.15 = 15 100 9 1000 (b) 0.009 = (c) 2.5 = 2 N1. (a) 0.8 = 5 25 = 10 10 8 10 (b) 0.431 = 431 1000 (c) 2.58 = 2 2. (a) 58 258 = 100 100 42.830 71.000 + 3.074 116.904 (b) 32.50 โˆ’ 21.72 10.78 N2. (a) 68.900 42.720 + 8.973 120.593 (b) 351.800 โˆ’ 2.706 349.094 3. (a) 30.2 1 decimal place ร— 0.052 3 decimal places 136. Estimate each fraction. 604 โ†“ 1510 1+ 3 = 4 1.5704 4 decimal places (b) 0.06 2 decimal places ร— 0.12 2 decimal places 12 โ†“ 6 2+2 = 4 0.0072 4 decimal places Copyright ยฉ 2020 Pearson Education, Inc. R.2 Decimals and Percents 17 N3. (a) 9.32 2 decimal places ร— 1.4 1 decimal place 3728 โ†“ 932 2 +1 = 3 13.048 3 decimal places (b) 0.6 1 decimal place ร— 0.004 3 decimal places 24 1+ 3 = 4 0.0024 4 decimal places 4. (a) To change the divisor 0.37 into a whole number, move each decimal point two places to the right. Move the decimal point straight up and divide as with whole numbers. 14.8 37 547.6 37 177 148 296 296 0 Therefore, 5.476 รท 0.37 = 14.8. (b) To change the divisor 3.1 into a whole number, move each decimal point one place to the right. Move the decimal point straight up and divide as with whole numbers. 1.21 31 37.60 31 66 62 40 31 9 We carried out the division to 2 decimal places so that we could round to 1 decimal place. Therefore, 3.76 รท 3.1 โ‰ˆ 1.2. N4. (a) To change the divisor 14.9 into a whole number, move each decimal point one place to the right. Move the decimal point straight up and divide as with whole numbers. 30.3 149 4514.7 447 447 447 0 Therefore, 451.47 รท 14.9 = 30.3. (b) To change the divisor 1.3 into a whole number, move each decimal point one place to the right. Move the decimal point straight up and divide as with whole numbers. 5.641 13 73.340 65 83 78 54 52 20 13 7 We carried out the division to 3 decimal places so that we could round to 2 decimal places. Therefore, 7.334 รท 1.3 โ‰ˆ 5.64. 5. (a) Move the decimal point three places to the right. 19.5 ร— 1000 = 19,500 (b) Move the decimal point one place to the left. 960.1 รท 10 = 96.01 N5. (a) Move the decimal point one place to the right. 294.72 ร— 10 = 2947.2 (b) Move the decimal point two places to the left. Insert a 0 in front of the 4 to do this. 4.793 รท 100 = 0.04793 Copyright ยฉ 2020 Pearson Education, Inc. 18 Chapter R Prealgebra Review 6. (a) Divide 3 by 50. Add a decimal point and as many 0s as necessary. 0.06 50 3.00 3 00 0 1 7. (a) 5 % = 5.25% 4 5.25 = 100 = 0.0525 (b) 200% = 3 = 0.06. Therefore, 50 (b) Divide 11 by 1. Add a decimal point and as many 0s as necessary. 0.090909… 11 1.000000… 99 100 N7. (a) 23% = 200 = 2.00, or 2 100 23 = 0.23 100 (b) 350% = 350 = 3.50, or 3.5 100 8. (a) 0.06 = 0.06 โ‹…100% = 6% (b) 1.75 = 1.75 โ‹…100% = 175% 99 100 N8. (a) 0.31 = 0.31 โ‹…100% = 31% 99 (b) 1.32 = 1.32 โ‹…100% = 132% 1 Note that the pattern repeats. Therefore, 1 = 0.09, or about 0.091. 11 N6. (a) Divide 20 by 17. Add a decimal point and as many 0s as necessary. 0.85 20 17.00 160 100 100 0 Therefore, 17 = 0.85. 20 (b) Divide 2 by 9. Add a decimal point and as many 0s as necessary. 0.222… 9 2.000… 18 20 18 20 18 2 Note that the pattern repeats. Therefore, 2 = 0.2, or 0.222. 9 9. (a) 85% = 0.85 (b) 110% = 1.10, or 1.1 (c) 0.30 = 30% (d) 0.165 = 16.5% N9. (a) 52% = 0.52 (b) 2% = 02% = 0.02 (c) 0.45 = 45% (d) 3.5 = 3.50 = 350% 65 100 In lowest terms, 65 13 โ‹… 5 13 = = 100 20 โ‹… 5 20 10. (a) 65% = (b) 1.5% = 1.5 1.5 10 15 3 = โ‹… = = 100 100 10 1000 200 20 100 In lowest terms, 20 1 โ‹… 20 1 = = 100 5 โ‹… 20 5 N10. (a) 20% = 160 100 In lowest terms, 160 8 โ‹… 20 8 3 = = , or 1 100 5 โ‹… 20 5 5 (b) 160% = Copyright ยฉ 2020 Pearson Education, Inc. R.2 Decimals and Percents 19 11. (a) Exercises 3 3 = โ‹…100% 50 50 3 100 % = โ‹… 50 1 3 โ‹… 50 โ‹… 2 % = 50 = 6% 1. 367.9412 (a) Tens: 6 (b) Tenths: 9 (c) Thousandths: 1 (d) Ones: 7 1 1 (b) = โ‹…100% 3 3 1 100 = โ‹… % 3 1 100 = % 3 1 = 33 %, or 33.3% 3 N11. (a) (b) (e) Hundredths: 4 2. Answers will vary. One example is 5243.0164. 3. 46.249 (a) 46.25 (b) 46.2 (c) 46 (d) 50 6 6 = โ‹…100% 25 25 6 100 = โ‹… % 25 1 6 โ‹… 25 โ‹… 4 = % 25 = 24% 4. (a) 0.889 (b) 0.444 (c) 0.976 (d) 0.865 7 7 = โ‹…100% 9 9 7 100 = โ‹… % 9 1 700 = % 9 7 = 77 %, or 77.7% 9 12. The discount is 30% of $69. The word of here means multiply. 30% of 69 โ†“ โ†“ โ†“ 0.30 โ‹… 69 = 20.7 The discount is $20.70. The sale price is found by subtracting. $69.00 โˆ’ $20.70 = $48.30 N12. The discount is 60% of $120. The word of here means multiply. 60% of 120 โ†“ โ†“ โ†“ 0.60 โ‹… 120 = 72 The discount is $72. The sale price is found by subtracting. $120.00 โˆ’ $72 = $48 5. 0.4 = 4 10 6. 0.6 = 6 10 7. 0.64 = 64 100 8. 0.82 = 82 100 9. 0.138 = 138 1000 10. 0.104 = 104 1000 11. 0.043 = 43 1000 12. 0.087 = 87 1000 13. 3.805 = 3 805 3805 = 1000 1000 14. 5.166 = 5 166 5166 = 1000 1000 Copyright ยฉ 2020 Pearson Education, Inc. 20 Chapter R Prealgebra Review 15. 16. 25.320 109.200 + 8.574 26. 143.094 27. 20.418 90.527 32.430 + 589.800 712.757 17. 28.73 โˆ’ 3.12 28. 19. 20. 43.50 โˆ’ 28.17 29. 2+2 = 4 22.41 2 decimal places ร— 33 0 decimal places โ†“ 739.53 2 decimal places 30. 3.87 15.00 + 2.90 8.20 1.09 + 12.00 32.560 47.356 + 1.800 75.200 123.960 + 3.897 203.057 25. โ†“ 345.10 โˆ’ 56.31 81.716 24. 34.04 2 decimal places ร— 0.56 2 decimal places 6723 6723 18.000 โˆ’ 2.789 15.211 2+0 = 2 55.76 2 decimal places ร— 72 0 decimal places โ†“ 11152 39032 2+0 = 2 4014.72 2 decimal places 31. 0.2 1 decimal place ร— 0.03 2 decimal places 6 1+ 2 = 3 0.006 3 decimal places 21.29 23. โ†“ 1+1 = 2 19.0624 4 decimal places 21.77 22. 128 1152 15.33 288.79 21. 1 decimal place 1 decimal place 20424 17020 46.88 โˆ’ 13.45 33.43 12.8 ร— 9.1 116.48 2 decimal places 25.61 18. 29.000 โˆ’ 8.582 32. 0.07 2 decimal places ร— 0.004 3 decimal places 28 2+3 = 5 0.00028 5 decimal places 7.15 33. 11 78.65 77 16 11 55 55 0 Copyright ยฉ 2020 Pearson Education, Inc. R.2 Decimals and Percents 21 5.24 34. 14 73.36 70 33 28 56 56 0 8.44 527 4447.88 4216 2318 2108 2108 2108 35. To change the divisor 11.6 into a whole number, move each decimal point one place to the right. Move the decimal point straight up and divide as with whole numbers. 2.8 116 324.8 232 092 8 0928 000 0 Therefore, 32.48 รท 11.6 = 2.8 . 36. To change the divisor 17.4 into a whole number, move each decimal point one place to the right. Move the decimal point straight up and divide as with whole numbers. 4.9 174 852.6 696 156 6 156 6 000 0 Therefore, 85.26 รท 17.4 = 4.9 . 37. To change the divisor 9.74 into a whole number, move each decimal point two places to the right. Move the decimal point straight up and divide as with whole numbers. 2.05 974 1996.70 1948 4870 4870 0 Therefore, 19.967 รท 9.74 = 2.05. 38. To change the divisor 5.27 into a whole number, move each decimal point two places to the right. Move the decimal point straight up and divide as with whole numbers. 0 Therefore, 44.4788 รท 5.27 = 8.44. 39. Move the decimal point one place to the right. 123.26 ร— 10 = 1232.6 40. Move the decimal point one place to the right. 785.91ร— 10 = 7859.1 41. Move the decimal point two places to the right. 57.116 ร— 100 = 5711.6 42. Move the decimal point two places to the right. 82.053 ร— 100 = 8205.3 43. Move the decimal point three places to the right. 0.094 ร— 1000 = 94 44. Move the decimal point three places to the right. 0.025 ร— 1000 = 25 45. Move the decimal point one place to the left. 1.62 รท 10 = 0.162 46. Move the decimal point one place to the left. 8.04 รท 10 = 0.804 47. Move the decimal point two places to the left. 124.03 รท 100 = 1.2403 48. Move the decimal point two places to the left. 490.35 รท 100 = 4.9035 49. Move the decimal point three places to the left. 23.29 รท 1000 = 023.29 รท 1000 = 0.02329 50. Move the decimal point three places to the left. 59.8 รท 1000 = 059.8 รท 1000 = 0.0598 51. Convert from a decimal to a percent. 0.01 = 0.01 โ‹…100% = 1% Fraction in Lowest Terms (or Whole Number) Decimal Percent 1 100 0.01 1% Copyright ยฉ 2020 Pearson Education, Inc. 22 Chapter R Prealgebra Review 52. Convert from a percent to a decimal. 2 2% = = 0.02 100 Fraction in Lowest Terms (or Whole Number) Decimal Percent 1 50 0.02 2% 53. Convert from a percent to a fraction. 5 5% = 100 In lowest terms, 5 1โ‹… 5 1 = = 100 20 โ‹… 5 20 Fraction in Lowest Terms (or Whole Number) Decimal Percent 1 20 0.05 5% 56. Convert the percent to a decimal first. 20% = 0.20, or 0.2 Convert from a percent to a fraction. 20 20% = 100 In lowest terms, 20 1 โ‹… 20 1 = = 100 5 โ‹… 20 5 Fraction in Lowest Terms (or Whole Number) Decimal Percent 1 5 0.2 20% 57. Convert to a decimal first. Divide 1 by 4. Add a decimal point and as many 0s as necessary. 0.25 4 1.00 8 20 20 54. Convert to a decimal first. Divide 1 by 10. Move the decimal point one place to the left. 1 รท 10 = 0.1 Convert the decimal to a percent. 0.1 = 0.1 โ‹…100% = 10% Fraction in Lowest Terms (or Whole Number) Decimal Percent 1 10 0.1 10% 0 Convert the decimal to a percent. 0.25 = 0.25 โ‹…100% = 25% Fraction in Lowest Terms (or Whole Number) Decimal Percent 1 4 0.25 25% 58. Convert to a decimal first. Divide 1 by 3. Add a decimal point and as many 0s as necessary. 0.33… 3 1.00… 9 55. Convert the decimal to a percent. 0.125 = 0.125 โ‹…100% = 12.5% Fraction in Lowest Terms (or Whole Number) Decimal Percent 1 8 0.125 12.5% 10 9 1 Note that the pattern repeats. Therefore, 1 = 0.3. 3 Convert the decimal to a percent. 1 0.333 = 0.333 โ‹…100% = 33.3%, or 33 % 3 Copyright ยฉ 2020 Pearson Education, Inc. R.2 Decimals and Percents 23 Fraction in Lowest Terms (or Whole Number) 1 3 Decimal Percent 0.3 33.3% or 1 33 % 3 59. Convert the percent to a decimal first. 50% = 0.50, or 0.5 Convert from a percentl to a fraction. 50 50% = 100 In lowest terms, 50 1 โ‹… 50 1 = = 100 2 โ‹… 50 2 Decimal Percent 1 2 0.5 50% 60. Divide 2 by 3. Add a decimal point and as many 0s as necessary. 0.66… 3 2.00… 18 20 18 2 Note that the pattern repeats. Therefore, 2 = 0.6. 3 2 3 Fraction in Lowest Terms (or Whole Number) Decimal Percent 3 4 0.75 75% 62. Convert the decimal to a percent. 1.0 = 1.0 โ‹…100% = 100% Fraction in Lowest Terms (or Whole Number) Fraction in Lowest Terms (or Whole Number) 61. Convert the decimal to a percent first. 0.75 = 0.75 โ‹…100% = 75% Convert from a percent to a fraction. 75 75% = 100 In lowest terms, 75 3 โ‹… 25 3 = = 100 4 โ‹… 25 4 Decimal Percent 0.6 66.6% or 2 66 % 3 Fraction in Lowest Terms (or Whole Number) Decimal Percent 1 1.0 100% 63. Divide 21 by 5. Add a decimal point and as many 0s as necessary. 4.2 5 21.0 20 010 010 000 64. Divide 9 by 5. Add a decimal point and as many 0s as necessary. 1.8 5 9.0 5 40 40 0 Copyright ยฉ 2020 Pearson Education, Inc. 24 Chapter R Prealgebra Review 65. Divide 9 by 4. Add a decimal point and as many 0s as necessary. 2.25 4 9.00 8 10 8 20 20 0 66. Divide 15 by 4. Add a decimal point and as many 0s as necessary. 3.75 4 15.00 12 30 28 20 20 0 67. Divide 3 by 8. Add a decimal point and as many 0s as necessary. 0.375 8 3.000 24 60 56 40 40 0 68. Divide 7 by 8. Add a decimal point and as many 0s as necessary. 0.875 8 7.000 64 60 56 40 40 0 69. Divide 5 by 9. Add a decimal point and as many 0s as necessary. 0.555… 9 5.000… 45 50 45 50 45 5 Note that the pattern repeats. Therefore, 5 = 0.5, or about 0.556. 9 70. Divide 8 by 9. Add a decimal point and as many 0s as necessary. 0.888… 9 8.000… 72 80 72 80 72 8 Note that the pattern repeats. Therefore, 8 = 0.8, or about 0.889. 9 71. Divide 1 by 6. Add a decimal point and as many 0s as necessary. 0.166… 6 1.000… 6 40 36 40 36 4 Note that the pattern repeats. Therefore, 1 = 0.16, or about 0.167. 6 Copyright ยฉ 2020 Pearson Education, Inc. R.2 Decimals and Percents 25 72. Divide 5 by 6. Add a decimal point and as many 0s as necessary. 0.833… 6 5.000… 48 20 18 20 18 2 Note that the pattern repeats. Therefore, 5 = 0.83, or about 0.833. 6 73. 54% = 0.54 74. 39% = 0.39 75. 7% = 07% = 0.07 78. 189% = 1.89 79. 2.4% = 02.4% = 0.024 80. 3.1% = 03.1% = 0.031 1 82. 5 % = 5.5% = 05.5% = 0.055 2 86. 0.83 = 83% 87. 0.02 = 2% 88. 0.08 = 8% 89. 0.004 = 0.4% 90. 0.005 = 0.5% 91. 1.28 = 128% 92. 2.35 = 235% 93. 0.40 = 40% 98. 47% = 47 100 15 100 In lowest terms, 15 3โ‹…5 3 = = 100 20 โ‹… 5 20 99. 15% = 35 100 In lowest terms, 35 7 โ‹…5 7 = = 100 20 โ‹… 5 20 100. 35% = 8 100 In lowest terms, 8 2โ‹…4 2 = = 100 25 โ‹… 4 25 102. 8% = 1 81. 6 % = 6.25% = 06.25% = 0.0625 4 85. 0.79 = 79% 51 100 101. 2% = 77. 117% = 1.17 84. 0.9% = 00.9% = 0.009 97. 51% = 2 100 In lowest terms, 2 1โ‹… 2 1 = = 100 50 โ‹… 2 50 76. 4% = 04% = 0.04 83. 0.8% = 00.8% = 0.008 96. 10 = 10.00 = 1000% 140 100 In lowest terms, 140 7 โ‹… 20 7 2 = = , or 1 100 5 โ‹… 20 5 5 103. 140% = 180 100 In lowest terms, 180 9 โ‹… 20 9 4 = = , or 1 100 5 โ‹… 20 5 5 104. 180% = 7.5 7.5 10 75 = โ‹… = 100 100 10 1000 In lowest terms, 75 3 โ‹… 25 3 = = 1000 40 โ‹… 25 40 105. 7.5% = 94. 0.6 = 0.60 = 60% 95. 6 = 6.00 = 600% Copyright ยฉ 2020 Pearson Education, Inc. 26 Chapter R Prealgebra Review 2.5 2.5 10 25 = โ‹… = 100 100 10 1000 In lowest terms, 25 1 โ‹… 25 1 = = 1000 40 โ‹… 25 40 106. 2.5% = 107. 108. 109. 110. 111. 115. 4 4 4 100 4 โ‹… 5 โ‹… 20 %= % = 80% = โ‹…100% = โ‹… 5 5 5 1 5 13 13 = โ‹…100% 6 6 13 100 = โ‹… % 6 1 13 โ‹… 2 โ‹… 50 % = 2โ‹…3 = 216.6% 31 31 = โ‹…100% 9 9 31 100 = โ‹… % 9 1 3100 % = 9 = 344.4% 3 3 = โ‹…100% 25 25 3 100 = โ‹… % 25 1 3 โ‹… 4 โ‹… 25 = % 25 = 12% 116. 7 7 = โ‹…100% 50 50 7 100 = โ‹… % 50 1 7 โ‹… 2 โ‹… 50 = % 50 = 14% 117. The word of here means multiply. 50% of 320 โ†“ โ†“ โ†“ 0.50 โ‹… 320 = 160 118. The word of here means multiply. 25% of 120 โ†“ โ†“ โ†“ 0.25 โ‹… 120 = 30 9 9 = โ‹…100% 20 20 9 100 = โ‹… % 20 1 9 โ‹… 5 โ‹… 20 = % 20 = 45% 119. The word of here means multiply. 6% of 80 โ†“ โ†“ โ†“ 0.06 โ‹… 80 = 4.8 120. The word of here means multiply. 5% of 70 โ†“ โ†“ โ†“ 0.05 โ‹… 70 = 3.5 2 2 = โ‹…100% 11 11 2 100 = โ‹… % 11 1 200 = % 11 = 18.18% 121. The word of here means multiply. 14% of 780 โ†“ โ†“ โ†“ 0.14 โ‹… 780 = 109.2 112. 4 4 4 100 400 = โ‹…100% = โ‹… %= % = 44.4% 9 9 9 1 9 113. 9 9 9 100 9 โ‹… 4 โ‹… 25 = โ‹…100% = โ‹… %= % = 225% 4 4 4 1 4 114. 8 8 8 100 8 โ‹… 5 โ‹… 20 = โ‹…100% = โ‹… %= % = 160% 5 5 5 1 5 122. The word of here means multiply. 26% of 480 โ†“ โ†“ โ†“ 0.26 โ‹… 480 = 124.8 Copyright ยฉ 2020 Pearson Education, Inc. R.2 Decimals and Percents 27 123. The tip is 20% of $89. The word of here means multiply. 20% of $89 โ†“ โ†“ โ†“ 0.20 โ‹… $89 = $17.80 The tip is $17.80. The total bill is found by adding. $89 + $17.80 = $106.80 124. The raise is 7% of $15. The word of here means multiply. 7% of $15 โ†“ โ†“ โ†“ 0.07 โ‹… $15 = $1.05 The amount of the raise is $1.05 per hour. The new hourly rate is found by adding. $15 + $1.05 = $16.05 129. First, find the portion of the circle graph that represents โ€œOther.โ€ 100% โˆ’ ( 26% + 25% + 19% + 15% ) = 15% The portion of the circle graph showing the number of travelers from โ€œOtherโ€ countries is 15% of the circle. 130. The portion of the circle graph showing the number of travelers from โ€œOtherโ€ countries is 15% of the circle. Find 15% of 76 million. 15% of 76 million โ†“ โ†“ โ†“ 0.15 โ‹… 76 million = 11.4 million, or approximately 11,400,000 travelers. 125. The discount is 15% of $795. The word of here means multiply. 15% of $795 โ†“ โ†“ โ†“ 0.15 โ‹… $795 = $119.25 The amount of the discount is $119.25. The sale price is found by subtracting. $795 โˆ’ $119.25 = $675.75 126. The discount is 20% of $597. The word of here means multiply. 20% of $597 โ†“ โ†“ โ†“ 0.20 โ‹… $597 = $119.40 The amount of the discount is $119.40. The sale price is found by subtracting. $597 โˆ’ $119.40 = $477.60 127. The portion of the circle graph showing the number of travelers from Canada is 26% of the circle. Find 26% of 76 million. 26% of 76 million โ†“ โ†“ โ†“ 0.26 โ‹… 76 million = 19.76 million, or approximately 19,760,000 travelers. 128. The portion of the circle graph showing the number of travelers from Mexico is 25% of the circle. Find 25% of 76 million. 25% of 76 million โ†“ โ†“ โ†“ 0.25 โ‹… 76 million = 19 million, or approximately 19,000,000 travelers. Copyright ยฉ 2020 Pearson Education, Inc. 28 Chapter 1 The Real Number System Chapter 1 The Real Number System 1.1 Exponents, Order of Operations, and Inequality N2. (a) 15 โˆ’ 2 โ‹… 6 = 15 โˆ’ 12 Multiply. Subtract. =3 (b) 8 + 2 ( 5 โˆ’ 1) = 8 + 2 ( 4 ) Subtract inside parentheses. Classroom Examples, Now Try Exercises 1. (a) 92 = 9 โ‹… 9 = 81 2 (c) (0.5) = 0.5 โ‹… 0.5 = 0.25 N1. (a) 62 = 6 โ‹… 6 = 36 3 4 4 4 64 ๏ƒฆ4๏ƒถ (b) ๏ƒง ๏ƒท = โ‹… โ‹… = 5 5๏€ด 5 125 ๏ƒจ5๏ƒธ ๏€ฑ ๏€ด๏€ฒ ๏€ณ 4 is used as a factor 3 times. 5 = 36 โˆ’ 35 Multiply. =1 Subtract. = 9 [12] = 108 (b) (b) 18 + 2 ( 6 โˆ’ 3) = 18 + 2 ( 3) Subtract inside parentheses. (c) 7 โ‹… 6 โˆ’ 3 ( 8 + 1) = 7 โ‹… 6 โˆ’ 3 ( 9 ) Add inside parentheses. = 42 โˆ’ 27 Multiply. = 15 Subtract. (d) 2 + 32 โˆ’ 5 โ‹… 2 = 2 + 9 โˆ’ 5 โ‹… 2 Apply exponents. = 2 + 9 โˆ’ 10 Multiply. = 11 โˆ’ 10 Add. =1 Subtract. Divide/multiply. Subtract. Add. = 9 [36 โˆ’ 2(12) ] Add inside parentheses. = 9 [36 โˆ’ 24] 2. (a) 10 โˆ’ 6 รท 2 = 10 โˆ’ 3 Divide. =7 Subtract. Apply exponents. Multiply. 3. (a) 9 [36 โˆ’ 2(4 + 8) ] (c) (0.7) = 0.7 โ‹… 0.7 = 0.49 Add. Add. (d) 8 โ‹…10 รท 4 โˆ’ 23 + 3 โ‹… 42 = 8 โ‹…10 รท 4 โˆ’ 8 + 3 โ‹…16 = 80 รท 4 โˆ’ 8 + 3 โ‹…16 = 20 โˆ’ 8 + 48 = 12 + 48 = 60 2 = 24 = 16 = 6 ( 6 ) โˆ’ 7 โ‹… 5 Add inside parentheses. 1 is used as a factor 4 times. 2 Multiply. Multiply. (c) 6 ( 2 + 4 ) โˆ’ 7 โ‹… 5 4 1 1 1 1 1 ๏ƒฆ1๏ƒถ (b) ๏ƒง ๏ƒท = โ‹… โ‹… โ‹… = 2 2๏€ด 2๏€ฒ๏€ด 2๏€ณ 2 16 ๏ƒจ ๏ƒธ ๏€ฑ = 18 + 6 = 8+8 2(7 + 8) + 2 3โ‹…5 +1 2(15) + 2 = 3โ‹…5 +1 30 + 2 = 15 + 1 32 = 16 =2 Multiply inside brackets. Subtract inside brackets. Multiply. Add inside parentheses. Multiply. Add. Divide. N3. (a) 7 [3(3 โˆ’ 1) + 4] = 7 [3(2) + 4] = 7 [ 6 + 4] = 7 [10] = 70 Copyright ยฉ 2020 Pearson Education, Inc. Subtract inside parentheses. Multiply inside brackets. Add inside brackets. Multiply. 1.1 Exponents, Order of Operations, and Inequality 29 (b) 9(14 โˆ’ 4) โˆ’ 2 4 + 3โ‹… 6 9(10) โˆ’ 2 = Subtract inside parentheses. 4 + 3โ‹… 6 90 โˆ’ 2 = Multiply. 4 + 18 88 = Subtract and add. 22 =4 Divide. 4. (a) The statement 12 > 6 is true because 12 is greater than 6. Note that the inequality symbol points to the lesser number. (b) The statement 28 โ‰  4 โ‹… 7 is false because 28 is equal to 4 โ‹… 7. (c) The statement 1 โ‰ค 0.1 is true because 10 1 = 0.1 10 N5. (a) โ€œTen is not equal to eight minus twoโ€ is written as 10 โ‰  8 โˆ’ 2. (b) โ€œFifty is greater than fifteenโ€ is written as 50 > 15. (c) โ€œEleven is less than or equal to twentyโ€ is written as 11 โ‰ค 20. 6. 9 โ‰ค 15 is equivalent to 15 โ‰ฅ 9. N6. 8 8. Exercises 1. False; 32 = 3 โ‹… 3 = 9. 2. False; 1 raised to any power is 1. Here, 13 = 1 โ‹…1 โ‹…1 = 1. 3. False; a number raised to the first power is that number, so 31 = 3. (d) Write the fractions with a common 1 1 denominator. The statement < is 3 4 4 3 4 โ‹… 2 is false because 5 is less than 8. (c) The statement (c) โ€œTwo is greater than or equal to twoโ€ is written as 2 โ‰ฅ 2. 1 โ‰ค 0.25 is true because 4 1 = 0.25 4 (d) Write the fractions with a common 5 7 is denominator. The statement > 9 11 55 63 > . equivalent to the statement 99 99 Because 55 is less than 63, the original statement is false. 5. (a) โ€œNine is equal to eleven minus twoโ€ is written as 9 = 11 โˆ’ 2. 4. False; 62 means that 6 is used as a factor 2 times, so 62 = 6 โ‹… 6 = 36. 5. False; the common error leading to 42 is adding 4 to 3 and then multiplying by 6. One must follow the rules for order of operations. 4 + 3(8 โˆ’ 2) = 4 + 3(6) = 4 + 18 = 22 6. False; multiplications and divisions are performed in order from left to right. 12 รท 2 โ‹… 3 = 6โ‹…3 = 18 7. Additions and subtractions are performed in order from left to right. 18 โˆ’ ๏ป 2+ ๏ป3 1 2 8. Multiplications and divisions are performed in order from left to right, and then additions and subtractions are performed in order from left to right. 28 โˆ’ ๏ป6รท ๏ป2 2 1 (b) โ€œFourteen is greater than twelveโ€ is written as 14 > 12. Copyright ยฉ 2020 Pearson Education, Inc. 30 Chapter 1 The Real Number System 9. Multiplications and divisions are performed in order from left to right, and then additions and subtractions are performed in order from left to right. 2๏ป โ‹…8โˆ’ ๏ป6รท ๏ป3 1 1 1 ๏ƒฆ1๏ƒถ 26. ๏ƒง ๏ƒท = โ‹… = 3 3 3 9 ๏ƒจ ๏ƒธ 10. Multiplications and divisions are performed in order from left to right, and then additions and subtractions are performed in order from left to right. If grouping symbols are present, work within them first, starting with the innermost. 40 + ๏ป 6( ๏ป 1) ๏ป 3โˆ’ 3 3 3 27 ๏ƒฆ3๏ƒถ 28. ๏ƒง ๏ƒท = โ‹… โ‹… = 4 4 4 4 64 ๏ƒจ ๏ƒธ 11. Multiplications and divisions are performed in order from left to right, and then additions and subtractions are performed in order from left to right. If grouping symbols are present, work within them first, starting with the innermost. 3๏ป โ‹…5โˆ’ ๏ป 2( ๏ป 2) ๏ป4+ 3 1 3 2 4 3 2 2 1 1 12. Apply all exponents. Then, multiplications and divisions are performed in order from left to right, and additions and subtractions are performed in order from left to right. 3 9โˆ’ ๏ป 2๏ป + ๏ป 3 ๏ปโ‹… 4 3 1 4 2 13. 7 2 = 7 โ‹… 7 = 49 14. 82 = 8 โ‹… 8 = 64 15. 122 = 12 โ‹…12 = 144 16. 142 = 14 โ‹…14 = 196 17. 43 = 4 โ‹… 4 โ‹… 4 = 64 18. 53 = 5 โ‹… 5 โ‹… 5 = 125 3 19. 10 = 10 โ‹…10 โ‹…10 = 1000 20. 113 = 11 โ‹…11 โ‹…11 = 1331 21. 34 = 3 โ‹… 3 โ‹… 3 โ‹… 3 = 81 22. 64 = 6 โ‹… 6 โ‹… 6 โ‹… 6 = 1296 23. 45 = 4 โ‹… 4 โ‹… 4 โ‹… 4 โ‹… 4 = 1024 24. 35 = 3 โ‹… 3 โ‹… 3 โ‹… 3 โ‹… 3 = 243 2 1 1 1 ๏ƒฆ1๏ƒถ 25. ๏ƒง ๏ƒท = โ‹… = 6 6 36 ๏ƒจ6๏ƒธ 2 4 2 2 2 2 16 ๏ƒฆ2๏ƒถ 27. ๏ƒง ๏ƒท = โ‹… โ‹… โ‹… = 3 3 3 3 81 ๏ƒจ3๏ƒธ 3 29. ( 0.6 )2 = 0.6 โ‹… 0.6 = 0.36 30. ( 0.9 )2 = 0.9 โ‹… 0.9 = 0.81 31. ( 0.4 )3 = 0.4 โ‹… 0.4 โ‹… 0.4 = 0.064 32. ( 0.5)4 = 0.5 โ‹… 0.5 โ‹… 0.5 โ‹… 0.5 = 0.0625 33. The multiplication should be performed before the addition. 8 + 2 โ‹… 3 = 8 + 6 Multiply. = 14 Add. The correct value of the expression is 14. 34. When cubing 2, the correct value is 2 โ‹… 2 โ‹… 2 = 8 , not 2 โ‹… 3 = 6 . 16 โˆ’ 23 + 5 = 16 โˆ’ 8 + 5 Apply exponents. Subtract. = 8+5 Add. = 13 The correct value of the expression is 13. 35. 64 รท 4 โ‹… 2 = 16 โ‹… 2 Divide. = 32 Multiply. 36. 250 รท 5 โ‹… 2 = 50 โ‹… 2 Divide. = 100 Multiply. 37. 13 + 9 โ‹… 5 = 13 + 45 Multiply. = 58 Add. 38. 11 + 7 โ‹… 6 = 11 + 42 Multiply. = 53 Add. 39. 25.2 โˆ’ 12.6 รท 4.2 = 25.2 โˆ’ 3 Divide. = 22.2 Subtract. 40. 12.4 โˆ’ 9.3 รท 3.1 = 12.4 โˆ’ 3 Divide. = 9.4 Subtract. 41. 9 โ‹… 4 โˆ’ 8 โ‹… 3 = 36 โˆ’ 24 Multiply. = 12 Subtract. Copyright ยฉ 2020 Pearson Education, Inc. 1.1 Exponents, Order of Operations, and Inequality 31 42. 11 โ‹… 4 + 10 โ‹… 3 = 44 + 30 Multiply. = 74 Add. 43. 44. 1 2 2 11 1 22 โ‹… + โ‹… = + 4 3 5 3 6 15 5 44 = + 30 30 49 19 , or 1 = 30 30 9 2 4 5 3 4 โ‹… + โ‹… = + 4 3 5 3 2 3 9 8 = + 6 6 17 5 = , or 2 6 6 Multiply. LCD = 30 Add. Multiply. LCD = 6 Add. 45. 20 โˆ’ 4 โ‹… 3 + 5 = 20 โˆ’ 12 + 5 Multiply. = 8+5 Subtract. Add. = 13 46. 18 โˆ’ 7 โ‹… 2 + 6 = 18 โˆ’ 14 + 6 Multiply. Subtract. = 4+6 Add. = 10 47. 10 + 40 รท 5 โ‹… 2 = 10 + 8 โ‹… 2 Divide. = 10 + 16 Multiply. = 26 Add. 48. 12 + 64 รท 8 โˆ’ 4 = 12 + 8 โˆ’ 4 Divide. Add. = 20 โˆ’ 4 Subtract. = 16 49. 18 โˆ’ 2(3 + 4) = 18 โˆ’ 2(7) Add inside parentheses. Multiply. = 18 โˆ’ 14 Subtract. =4 50. 30 โˆ’ 3 ( 4 + 2 ) = 30 โˆ’ 3 ( 6 ) Add inside parentheses. = 30 โˆ’ 18 Multiply. = 12 Subtract. 51. 3(4 + 2) + 8 โ‹… 3 = 3 โ‹… 6 + 8 โ‹… 3 Add. = 18 + 24 Multiply. Add. = 42 53. 18 โˆ’ 42 + 3 = 18 โˆ’ 16 + 3 Apply exponents. Subtract. = 2+3 Add. =5 54. 22 โˆ’ 23 + 9 = 22 โˆ’ 8 + 9 Apply exponents. Subtract. = 14 + 9 Add. = 23 55. 2 + 3[5 + 4(2)] = 2 + 3[5 + 8] = 2 + 3[13] = 2 + 39 = 41 Multiply. Add. Multiply. Add. 56. 5 + 4 ๏ƒซ๏ƒฉ1 + 7 ( 3) ๏ƒป๏ƒน = 5 + 4 [1 + 21] Multiply. = 5 + 4 [ 22] = 5 + 88 = 93 ( ) 57. 5 ๏ƒฉ3 + 4 22 ๏ƒน = 5[3 + 4(4)] ๏ƒซ ๏ƒป = 5(3 + 16) = 5(19) = 95 Add. Multiply. Add. Apply exponents. Multiply. Add. Multiply. ( ) 58. 6 ๏ƒฉ 2 + 8 33 ๏ƒน ๏ƒซ ๏ƒป = 6 [ 2 + 8 โ‹… 27 ] = 6(2 + 216) = 6 โ‹… 218 = 1308 Apply exponents. Multiply. Add. Multiply. 59. 32 [(11 + 3) โˆ’ 4] = 32 [14 โˆ’ 4] Add inside parentheses. = 32 [10] Subtract. = 9[10] Apply exponents. = 90 Multiply. 60. 42 [(13 + 4) โˆ’ 8] = 42 [17 โˆ’ 8] Add inside parentheses. = 42 [9] = 16 [9] = 144 52. 9 (1 + 7 ) + 2 โ‹… 5 = 9 โ‹… 8 + 2 โ‹… 5 Add. = 72 + 10 Multiply. = 82 Add. Copyright ยฉ 2020 Pearson Education, Inc. Subtract. Apply exponents. Multiply. 32 Chapter 1 The Real Number System 61. Simplify the numerator and denominator separately, and then divide. ( ) 6 32 โˆ’ 1 + 8 8โˆ’2 2 6(9 โˆ’ 1) + 8 8โˆ’4 6(8) + 8 = 4 48 + 8 = 4 56 = = 14 4 67. 10 โˆ’ 7 โˆ’ 3 = 6 10 โˆ’ (7 โˆ’ 3) = 10 โˆ’ 4 = 6 = 68. 8 + 22 = 100 (8 + 2 )2 = 102 = 10 โ‹…10 = 100 62. Simplify the numerator and denominator separately, and then divide. ( ) 2 82 โˆ’ 4 + 8 29 โˆ’ 33 = = 66. 2 โ‹… 8 โˆ’ 1 โ‹… 3 = 42 2 โ‹… ( 8 โˆ’ 1) โ‹… 3 = 2 โ‹… 7 โ‹… 3 = 14 โ‹… 3 = 42 69. 9 โ‹… 3 โˆ’ 11 โ‰ค 16 27 โˆ’ 11 โ‰ค 16 16 โ‰ค 16 The statement is true since 16 = 16. 70. 6 โ‹… 5 โˆ’ 12 โ‰ค 18 30 โˆ’ 12 โ‰ค 18 18 โ‰ค 18 The statement is true since 18 = 18. 2 ( 64 โˆ’ 4 ) + 8 29 โˆ’ 27 2 ( 60 ) + 8 2 120 + 8 = 2 128 = = 64 2 63. Simplify the numerator and denominator separately, and then divide. 4(6 + 2) + 8(8 โˆ’ 3) 4(8) + 8(5) = 6(4 โˆ’ 2) โˆ’ 22 6(2) โˆ’ 22 4(8) + 8(5) = 6(2) โˆ’ 4 32 + 40 = 12 โˆ’ 4 72 = =9 8 64. Simplify the numerator and denominator separately, and then divide. 6(5 + 1) โˆ’ 9(1 + 1) 6(6) โˆ’ 9(2) = 5(8 โˆ’ 6) โˆ’ 23 5(2) โˆ’ 23 36 โˆ’ 18 = 10 โˆ’ 8 18 = =9 2 65. 3 โ‹… 6 + 4 โ‹… 2 = 60 Listed below are some possibilities. Use trial and error until you get the desired result. (3 โ‹… 6) + 4 โ‹… 2 = 18 + 8 = 26 โ‰  60 (3 โ‹… 6 + 4) โ‹… 2 = 22 โ‹… 2 = 44 โ‰  60 3 โ‹… (6 + 4 โ‹… 2) = 3 โ‹…14 = 42 โ‰  60 3 โ‹… (6 + 4) โ‹… 2 = 3 โ‹…10 โ‹… 2 = 30 โ‹… 2 = 60 71. 5 โ‹…11 + 2 โ‹… 3 โ‰ค 60 55 + 6 โ‰ค 60 61 โ‰ค 60 The statement is false since 61 is greater than 60. 72. 9 โ‹… 3 + 4 โ‹… 5 โ‰ฅ 48 27 + 20 โ‰ฅ 48 47 โ‰ฅ 48 The statement is false since 47 is less than 48. 73. 0 โ‰ฅ 12 โ‹… 3 โˆ’ 6 โ‹… 6 0 โ‰ฅ 36 โˆ’ 36 0โ‰ฅ0 The statement is true since 0 = 0. 74. 10 โ‰ค 13 โ‹… 2 โˆ’ 15 โ‹…1 10 โ‰ค 26 โˆ’ 15 10 โ‰ค 11 The statement is true since 10 72 [12 + 10] โ‹… 3 > 72 [22] โ‹… 3 > 72 66 > 72 The statement is false since 66 is less than 72. 78. 2 โ‹… [7 โ‹… 5 โˆ’ 3(2)] โ‰ค 58 2 โ‹… [35 โˆ’ 6] โ‰ค 58 2[29] โ‰ค 58 58 โ‰ค 58 The statement is true since 58 = 58. 79. 80. 3 + 5(4 โˆ’ 1) โ‰ฅ3 2 โ‹… 4 +1 3 + 5(3) โ‰ฅ3 8 +1 3 + 15 โ‰ฅ3 9 18 โ‰ฅ3 9 2โ‰ฅ3 The statement is false since 2 is less than 3. 7 ( 3 + 1) โˆ’ 2 3+ 5โ‹… 2 7 ( 4) โˆ’ 2 2(5 + 1) โˆ’ 3(1 + 1) 5(8 โˆ’ 6) โˆ’ 4 โ‹… 2 2(6) โˆ’ 3(2) 3โ‰ฅ 5(2) โˆ’ 8 12 โˆ’ 6 3โ‰ฅ 10 โˆ’ 8 6 3โ‰ฅ 2 3โ‰ฅ3 The statement is true since 3 = 3. 81. 3 โ‰ฅ 82. 7 โ‰ค 3(8 โˆ’ 3) + 2(4 โˆ’ 1) 9(6 โˆ’ 2) โˆ’ 11( 5 โˆ’ 2 ) 3(5) + 2(3) 9(4) โˆ’ 11(3) 15 + 6 7โ‰ค 36 โˆ’ 33 21 7โ‰ค 3 7โ‰ค7 The statement is true since 7 = 7. 7โ‰ค 83. โ€œ5 < 17โ€ means โ€œfive is less than seventeen.โ€ The statement is true. 84. โ€œ8 2.50โ€ means โ€œtwo and five-tenths is greater than two and fifty-hundredths.โ€ The statement is false. 94. โ€œ1.80 > 1.8โ€ means โ€œone and eighty-hundredths is greater than one and eight-tenths.โ€ The statement is false. 95. โ€œFifteen is equal to five plus tenโ€ is written as 15 = 5 + 10. (c) 85% of 9.5 is 0.85(9.5) = 8.075. Walking at 5 mph is associated with 8.0 METs, which is the table value closest to 8.075. (d) Substitute โ€œ55โ€ for โ€œageโ€ in the expression for men. 14.7 โˆ’ 55 โ‹… 0.11 14.7 โˆ’ 55 โ‹… 0.11 = 14.7 โˆ’ 6.05 Multiply. 96. โ€œTwelve is equal to twenty minus eightโ€ is written as 12 = 20 โˆ’ 8. = 8.65 Subtract. 85% of 8.65 is 0.85(8.65) = 7.3525. Swimming is associated with 7.0 METs, which is the table value closest to 7.3525. 97. โ€œNine is greater than five minus fourโ€ is written as 9 > 5 โˆ’ 4. 98. โ€œTen is greater than six plus oneโ€ is written as 10 > 6 + 1. 110. Answers will vary. 99. โ€œSixteen is not equal to nineteenโ€ is written as 16 โ‰  19. 111. The states that had a number greater than 12.6 are Alaska (16.4), Texas (15.2), California (22.5), and Idaho (19.7). 100. โ€œThree is not equal to fourโ€ is written as 3 โ‰  4. 101. โ€œOne-half is less than or equal to two-fourthsโ€ 1 2 is written as โ‰ค . 2 4 102. โ€œOne-third is less than or equal to three-ninthsโ€ 1 3 is written as โ‰ค . 3 9 103. 5 5 when the inequality symbol is reversed. 104. 30 > 9 becomes 9 becomes < when the inequality 5 4 4 5 symbol is reversed. 5 3 3 5 106. when the inequality 4 2 2 4 symbol is reversed. 107. 2.5 โ‰ฅ 1.3 becomes 1.3 โ‰ค 2.5 when the inequality symbol is reversed. 108. 4.1 โ‰ค 5.3 becomes 5.3 โ‰ฅ 4.1 when the inequality symbol is reversed. 109. (a) Substitute โ€œ40โ€ for โ€œageโ€ in the expression for women. 14.7 โˆ’ 40 โ‹… 0.13 (b) 14.7 โˆ’ 40 โ‹… 0.13 = 14.7 โˆ’ 5.2 Multiply. = 9.5 Subtract. 112. The states that had a number that was at most 15.2 are Texas (15.2), Virginia (12.6), Maine (12.4), and Missouri (12.1). 113. The states that had a number not less than 12.6, which is the same as greater than or equal to 12.6, are Alaska (16.4), Texas (15.2), California (22.5), Virginia (12.6), and Idaho (19.7). 114. The states that had a number less than 13.0 are Virginia (12.6), Maine (12.4), and Missouri (12.1). 1.2 Variables, Expressions, and Equations Classroom Examples, Now Try Exercises 1. (a) 16 p โˆ’ 8 = 16 โ‹… 3 โˆ’ 8 = 48 โˆ’ 8 =40 (b) 2 p3 = 2 โ‹… 33 Replace p with 3. Multiply. Subtract. Replace p with 3. = 2 โ‹… 27 Cube 3. = 54 Multiply. N1. (a) 9 x โˆ’ 5 = 9 โ‹… 6 โˆ’ 5 = 54 โˆ’ 5 = 49 (b) Replace x with 6. Multiply. Subtract. 4 x 2 = 4 โ‹… 62 Replace x with 6. = 4 โ‹… 36 Square 6. = 144 Copyright ยฉ 2020 Pearson Education, Inc. Multiply. 1.2 Variables, Expressions, and Equations 35 (b) โ€œA number divided by 7โ€ translates as x x รท 7, or . 7 2. (a) 4 x + 5 y = 4 โ‹… 6 + 5 โ‹… 9 Multiply. = 24 + 45 Add. = 69 4x โˆ’ 2 y 4 โ‹… 6 โˆ’ 2 โ‹… 9 = (b) 6 +1 x +1 24 โˆ’ 18 = Multiply. 6 +1 6 = Subtract and add . 7 2 2 2 (c) โ€œThe difference between 9 and a numberโ€ translates as 9 โˆ’ x. Thus, โ€œthe product of 3 and the difference between 9 and a numberโ€ translates as 3(9 โˆ’ x). 4. (a) 8 p โˆ’ 10 = 5 ? 8 โ‹… 2 โˆ’ 10 = 5 2 (c) 2 x + y = 2 โ‹… 6 + 9 = 2 โ‹… 36 + 81 Use exponents. = 72 + 81 Multiply. = 153 Add. ? 16 โˆ’ 10 = 5 2 2 2 2 (c) 4 x โˆ’ y = 4 โ‹… 4 โˆ’ 7 = 4 โ‹…16 โˆ’ 49 Use exponents. = 64 โˆ’ 49 Multiply. = 15 Subtract. 3. (a) โ€œThe difference ofโ€ indicates subtraction. Using x as the variable to represent the number, โ€œthe difference of 48 and a numberโ€ translates as 48 โˆ’ x . (b) โ€œDivided byโ€ indicates division. Using x as the variable to represent the number, โ€œ6 divided by a numberโ€ translates as 6 รท x or 6 . x (c) โ€œThe sum of a number and 5โ€ suggests a number plus 5. Using x as the variable to represent the number, โ€œ9 multiplied by the sum of a number and 5โ€ translates as 9 ( x + 5) . Multiply. 6 = 5 False The number 2 is not a solution of the equation. (b) 0.1( x + 3) = 0.8 N2. (a) 3x + 4 y = 3 โ‹… 4 + 4 โ‹… 7 = 12 + 28 Multiply. = 40 Add. 6x โˆ’ 2 y 6 โ‹… 4 โˆ’ 2 โ‹… 7 = (b) 2y โˆ’ 9 2โ‹…7 โˆ’ 9 24 โˆ’ 14 = Multiply. 14 โˆ’ 9 10 =2 Subtract; reduce. = 5 Replace p with 2. ? 0.1(5 + 3) = 0.8 Replace x with 5. ? 0.1(8) = 0.8 Add. 0.8 = 0.8 True The number 5 is a solution of the equation. N4. 8k + 5 = 61 ? 8 โ‹… 7 + 5 = 61 Replace k with 7. ? 56 + 5 = 61 Multiply. 61 = 61 True The number 7 is a solution of the equation. 5. Using x as the variable to represent the number, โ€œthree times a number is subtracted from 21, giving 15โ€ translates as 21 โˆ’ 3x = 15. Now try each number from the set {0, 2, 4, 6, 8, 10}. ? x = 0 : 21 โˆ’ 3 ( 0 ) =15 21 = 15 False ? x = 2 : 21 โˆ’ 3 ( 2 ) =15 15 = 15 True ? x = 4 : 21 โˆ’ 3 ( 4 ) =15 9 = 15 False Similarly, x = 6, 8, or 10 result in false statements. Thus, 2 is the only solution. N3. (a) Using x as the variable to represent the number, โ€œthe sum of a number and 10โ€ translates as x + 10, or 10 + x. Copyright ยฉ 2020 Pearson Education, Inc. 36 Chapter 1 The Real Number System N5. Using x as the variable to represent the number, โ€œthe sum of a number and nine is equal to the difference between 25 and the numberโ€ translates as x + 9 = 25 โˆ’ x. Now try each number from the set {0, 2, 4, 6, 8, 10}. ? x = 4 : 4 + 9 = 25 โˆ’ 4 13 = 21 False ? x = 6 : 6 + 9 = 25 โˆ’ 6 15 = 19 False ? x = 8 : 8 + 9 = 25 โˆ’ 8 17 = 17 True Similarly, x = 0, 2, or 10 result in false statements. Thus, 8 is the only solution. 6. (a) (b) 3x โˆ’ 1 has no equality symbol, so this is an 5 expression. 3x = 1 has an equality symbol, so this is an 5 equation. N6. (a) 2 x + 5 = 6 has an equality symbol, so this is an equation. (b) 2 x + 5 โˆ’ 6 has no equality symbol, so this is an expression. Exercises 1. The expression 8x 2 means 8 โ‹… x โ‹… x. The correct choice is B. 6. There is no equality symbol in 6 x + 7 or 6 x โˆ’ 7, so those are expressions. 6 x = 7 and 6 x โˆ’ 7 = 0 have equality symbols, so those are equations. 7. The exponent refers only to the 4. 5 x 2 = 5 โ‹… 42 = 5 โ‹…16 = 80 The correct value is 80. 8. Addition in the numerator comes before division. x + 3 10 + 3 = 5 5 13 = 5 13 The correct value is . 5 9. (a) x + 7 = 4 + 7 = 11 (b) x + 7 = 6 + 7 = 13 10. (a) x โˆ’ 3 = 4 โˆ’ 3 =1 (b) x โˆ’ 3 = 6 โˆ’ 3 =3 11. (a) 4 x = 4 โ‹… 4 = 16 (b) 4 x = 4 โ‹… 6 = 24 2. If x = 2 and y = 1, then the value of xy is 2 โ‹…1 = 2. The correct choice is C. 12. (a) 6 x = 6 โ‹… 4 = 24 3. The sum of 15 and a number x is represented by the expression 15 + x. The correct choice is A. 13. (a) 5 x โˆ’ 4 = 5 โ‹… 4 โˆ’ 4 = 20 โˆ’ 4 = 16 4. 7 less than a number x is represented by the expression x โˆ’ 7 . The correct choice is D. 5. Try each number in the equation 3x โˆ’ 1 = 5 . ? x = 0 : 3 โ‹… 0 โˆ’ 1= 5 ? 0 โˆ’ 1= 5 โˆ’1 = 5 False ? x = 2 : 3 โ‹… 2 โˆ’ 1= 5 ? 6 โˆ’ 1= 5 5 = 5 False (b) 6 x = 6 โ‹… 6 = 36 (b) 5 x โˆ’ 4 = 5 โ‹… 6 โˆ’ 4 = 30 โˆ’ 4 = 26 14. (a) 7 x โˆ’ 9 = 7 โ‹… 4 โˆ’ 9 = 28 โˆ’ 9 = 19 (b) 7 x โˆ’ 9 = 7 โ‹… 6 โˆ’ 9 = 42 โˆ’ 9 = 33 Copyright ยฉ 2020 Pearson Education, Inc. 1.2 Variables, Expressions, and Equations 37 15. (a) 4 x 2 = 4 โ‹… 42 = 4 โ‹…16 = 64 (b) 4 x 2 = 4 โ‹… 62 = 4 โ‹… 36 = 144 2 2 16. (a) 5 x = 5 โ‹… 4 = 5 โ‹…16 = 80 (b) 5 x 2 = 5 โ‹… 62 = 5 โ‹… 36 = 180 17. (a) (b) 18. (a) x +1 4 +1 = 3 3 5 = 3 x +1 6 +1 = 3 3 7 = 3 x+2 4+2 = 5 5 6 = 5 x+2 6+2 = (b) 5 5 8 = 5 19. (a) (b) 3x โˆ’ 5 3 โ‹… 4 โˆ’ 5 = 2x 2โ‹…4 12 โˆ’ 5 = 8 7 = 8 3x โˆ’ 5 3 โ‹… 6 โˆ’ 5 = 2x 2โ‹…6 18 โˆ’ 5 = 12 13 = 12 20. (a) (b) 4x โˆ’1 4 โ‹… 4 โˆ’1 = 3x 3โ‹… 4 16 โˆ’ 1 = 12 15 5 = = 12 4 4x โˆ’1 4 โ‹… 6 โˆ’1 = 3x 3โ‹… 6 24 โˆ’ 1 = 18 23 = 18 21. (a) 3x 2 + x = 3 โ‹… 42 + 4 = 3 โ‹…16 + 4 = 48 + 4 = 52 (b) 3x 2 + x = 3 โ‹… 62 + 6 = 3 โ‹… 36 + 6 = 108 + 6 = 114 22. (a) 2 x + x 2 = 2 โ‹… 4 + 42 = 8 + 16 = 24 (b) 2 x + x 2 = 2 โ‹… 6 + 62 = 12 + 36 = 48 23. (a) 6.459 x = 6.459 โ‹… 4 = 25.836 (b) 6.459 x = 6.459 โ‹… 6 = 38.754 24. (a) 3.275 x = 3.275 โ‹… 4 = 13.1 (b) 3.275 x = 3.275 โ‹… 6 = 19.65 25. (a) 8 x + 3 y + 5 = 8 โ‹… 2 + 3 โ‹…1 + 5 = 16 + 3 + 5 = 19 + 5 = 24 (b) 8 x + 3 y + 5 = 8 โ‹…1 + 3 โ‹… 5 + 5 = 8 + 15 + 5 = 23 + 5 = 28 Copyright ยฉ 2020 Pearson Education, Inc. 38 Chapter 1 The Real Number System 26. (a) 4 x + 2 y + 7 = 4(2) + 2(1) + 7 = 8+ 2+7 = 17 31. (a) (b) 4 x + 2 y + 7 = 4(1) + 2(5) + 7 = 4 + 10 + 7 = 21 27. (a) 3( x + 2 y ) = 3(2 + 2 โ‹…1) = 3(2 + 2) = 3(4) = 12 (b) 3( x + 2 y ) = 3(1 + 2 โ‹… 5) = 3(1 + 10) = 3(11) (b) 32. (a) = 33 28. (a) 2(2 x + y ) = 2 ๏ƒฉ๏ƒซ 2 ( 2 ) + 1๏ƒน๏ƒป = 2 ( 4 + 1) = 2 (5) = 10 (b) (b) 2(2 x + y ) = 2 ๏ƒฉ๏ƒซ 2 (1) + 5๏ƒน๏ƒป = 2 ( 2 + 5) = 2 (7) = 14 29. (a) x + 4 4 = 2+ 1 y = 2+4 33. (a) =6 (b) x + 30. (a) y + 4 4 = 1+ 5 y 5 4 = + 5 5 9 = 5 8 8 = 1+ 2 x = 1+ 4 (b) x y 2 1 + = + 2 3 2 3 6 2 = + 6 6 8 4 = = 6 3 x y 1 5 + = + 2 3 2 3 3 10 = + 6 6 13 = 6 x y 2 1 + = + 5 4 5 4 8 5 = + 20 20 13 = 20 x y 1 5 + = + 5 4 5 4 4 25 = + 20 20 29 = 20 2 x + 4 y 2 โ‹… 2 + 4 โ‹…1 = 5 x + 2 y 5 โ‹… 2 + 2 โ‹…1 4+4 = 10 + 2 8 = 12 2 = 3 2 x + 4 y 2 โ‹…1 + 4 โ‹… 5 = 5 x + 2 y 5 โ‹…1 + 2 โ‹… 5 2 + 20 = 5 + 10 22 = 15 =5 (b) y + 8 8 = 5+ x 1 = 5+8 = 13 Copyright ยฉ 2020 Pearson Education, Inc. 1.2 Variables, Expressions, and Equations 39 34. (a) (b) 7 x + 5 y 7(2) + 5(1) = 8x + y 8(2) + 1 14 + 5 = 16 + 1 19 = 17 7 x + 5 y 7(1) + 5(5) = 8x + y 8(1) + 5 7 + 25 = 8+5 32 = 13 35. (a) 3x 2 + y 2 = 3 โ‹… 22 + 12 = 3โ‹… 4 +1 = 12 + 1 = 13 (b) 3x 2 + y 2 = 3 โ‹…12 + 52 = 3 โ‹…1 + 25 = 3 + 25 = 28 36. (a) 4 x 2 + 2 y 2 = 4 โ‹… 22 + 2 โ‹…12 = 4 โ‹… 4 + 2 โ‹…1 = 16 + 2 = 18 (b) 4 x 2 + 2 y 2 = 4 โ‹…12 + 2 โ‹… 52 = 4 โ‹…1 + 2 โ‹… 25 = 4 + 50 = 54 37. (a) 3x + y 2 3 โ‹… 2 + 12 = 2 x + 3 y 2 โ‹… 2 + 3 โ‹…1 3โ‹… 2 +1 = 4+3 6 +1 = 7 7 = 7 =1 (b) 38. (a) 3x + y 2 3 โ‹… 1 + 52 = 2 x + 3 y 2 โ‹…1 + 3 โ‹… 5 3 โ‹…1 + 25 = 2 + 15 3 + 25 = 17 28 = 17 x2 + 1 22 + 1 = 4 x + 5 y 4 ( 2 ) + 5 (1) 4 +1 8+5 5 = 13 = (b) 12 + 1 x2 + 1 = 4 x + 5 y 4 (1) + 5 ( 5 ) 1+1 4 + 25 2 = 29 = 39. (a) 0.841x 2 + 0.32 y 2 = 0.841 โ‹… 22 + 0.32 โ‹…12 = 0.841 โ‹… 4 + 0.32 โ‹…1 = 3.364 + 0.32 = 3.684 (b) 0.841x 2 + 0.32 y 2 = 0.841 โ‹…12 + 0.32 โ‹… 52 = 0.841 โ‹…1 + 0.32 โ‹… 25 = 0.841 + 8 = 8.841 40. (a) 0.941x 2 + 0.25 y 2 2 = 0.941( 2 ) + 0.25 (1) 2 = 0.941( 4 ) + 0.25 (1) = 3.764 + 0.25 = 4.014 (b) 0.941x 2 + 0.25 y 2 2 = 0.941(1) + 0.25 ( 5 ) 2 = 0.941(1) + 0.25 ( 25 ) = 0.941 + 6.25 = 7.191 Copyright ยฉ 2020 Pearson Education, Inc. 40 Chapter 1 The Real Number System 41. โ€œTwelve times a numberโ€ translates as 12 โ‹… x, or 12x. 57. ? 2 โ‹… 3 + 3(3 โˆ’ 2) = 14 42. โ€œFifteen times a numberโ€ translates as 15 โ‹… x, or 15x. 2 โ‹… 3 + 3 โ‹…1 = 14 ? 6 + 3 = 14 9 = 14 False Because substituting 3 for y results in a false statement, 3 is not a solution of the equation. 44. โ€œSix added to a numberโ€ translates as x + 6. 58. 6 x + 2 ( x + 3) = 14; 2 46. โ€œSeven subtracted from a numberโ€ translates as x โˆ’ 7. 6 ( 2 ) + 2(2 + 3) = 14 47. โ€œA number subtracted from sevenโ€ translates as 7 โˆ’ x. 6 ( 2 ) + 2 ( 5 ) = 14 ? ? 12 + 10 = 14 22 = 14 False The false result shows that 2 is not a solution of the equation. 49. โ€œThe difference between a number and 8โ€ translates as x โˆ’ 8. 59. 6 p + 4 p + 9 = 11; 1 5 ? 1 1 1 6 โ‹… + 4 โ‹… + 9 = 11 Let p = . 5 5 5 ? 6 4 + + 9 = 11 5 5 ? 10 + 9 = 11 5 18 . 51. โ€œ18 divided by a numberโ€ translates as x 52. โ€œA number divided by 18โ€ translates as Let x = 2. ? 48. โ€œA number subtracted from fourโ€ translates as 4 โˆ’ x. 50. โ€œThe difference between 8 and a numberโ€ translates as 8 โˆ’ x. Let y = 3. ? 43. โ€œAdded toโ€ indicates addition. โ€œNine added to a numberโ€ translates as x + 9. 45. โ€œTwo subtracted from a numberโ€ translates as x โˆ’ 2. 2 y + 3( y โˆ’ 2) = 14; 3 x . 18 53. โ€œThe product of 6 and four less than a numberโ€ translates as 6 ( x โˆ’ 4 ) . ? 2 + 9 = 11 11 = 11 True 54. โ€œThe product of 9 and five more than a numberโ€ translates as 9 ( x + 5 ) . The true result shows that 55. 4m + 2 = 6;1 equation. ? 4 โ‹…1 + 2 = 6 Let m = 1. 60. ? 4+2 = 6 6=6 True Because substituting 1 for m results in a true statement, 1 is a solution of the equation. 56. 2r + 6 = 8; 1 ? 2(1) + 6 = 8 Let r = 1. ? 2+6 =8 8=8 True The true result shows that 1 is a solution of the equation. 2 x + 3x + 8 = 20; 12 5 ? ๏ƒฆ 12 ๏ƒถ ๏ƒฆ 12 ๏ƒถ 2 ๏ƒง ๏ƒท + 3 ๏ƒง ๏ƒท + 8 = 20 ๏ƒจ 5๏ƒธ ๏ƒจ 5๏ƒธ 24 36 40 ? + + = 20 5 5 5 100 ? = 20 5 20 = 20 The true result shows that the equation. Copyright ยฉ 2020 Pearson Education, Inc. 1 is a solution of the 5 Let x = 12 . 5 True 12 is a solution of 5

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